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Anna11 [10]
3 years ago
13

Draw an energy diagram for an endothermic and exothermic reaction and label the diagram ​

Chemistry
2 answers:
just olya [345]3 years ago
5 0
Energy diagram for and endothermic and exothermic reaction

Molodets [167]3 years ago
5 0
Here they are.
Endothermic and exothermic reaction diagrams (labeled):

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Draw the structural formula of (3e,5e)-2,5-dibromo-3,5-octadiene.
mrs_skeptik [129]

We need draw the structure of (3E,5E)-2,5-dibromo-3,5-octadiene.

The structure is shown below:

The molecule has two double bonds in 3 and 5 position and two Br-atoms attached to 2 and 5 position.

The configuration is 3E and 5E. E configuration indicates cis- isomers where similar groups are in same side with respect to double bonds.

4 0
3 years ago
The chemical elements display periodicity when they're arranged according toQuestion 10 options:A) atomic mass.B) atomic volume.
BartSMP [9]

The periodic table is an ordered way of representing chemical elements. They were ordered according to their atomic number, remember that the atomic number corresponds to the number of protons of the elements.

So the answer will be option C) Atomic Number

5 0
1 year ago
Answer 22 and 23 please
Wittaler [7]
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6 0
3 years ago
At 25°C, gas in a rigid cylinder with a movable piston has a volume of 145 mL and a pressure of 125 kPa. Then the gas is compres
natta225 [31]

Answer:

(4) 230 kPa

Explanation:

The temperature is constant, so the only variables are pressure and volume.

We can use Boyle’s Law.

p_{1}V_{1} = p_{2}V_{2}

Divide both sides of the equation by V_{2}.

p_{2} = p_{1} \times \frac{V_{1}}{ V_{2}}

p_{1} = \text{145 kPa}; V_{1} = \text{125 cm}^{3}}

p_{2} = ?; V_{2} = \text{80. cm}^{3}

p_{2} = \text{145 kPa} \times \frac{\text{125 cm}^{3}}{\text{80. cm}^{3}} = \textbf{230 kPa}

7 0
3 years ago
What is the mass in grams of 9.76 x 10 12 atoms of naturally occurring sodium?
Fiesta28 [93]
The number of moles in a substance indicates the amount of the substance that contains the same number of particles as 12 g of the Carbon-12 isotope [or equivalent to 6.02 × 10²³] (which is used as a standard in the world of moles).

Now,

          if     6.02 × 10²³ atoms are found in 1 mole ofsodium
   then let  9.76 × 10¹² atoms are found in     x

⇒     x  =    (9.76 × 10¹² )  ÷  (6.02 × 10²³)

            =  1.619 × 10⁻¹¹ mol


Now, mass = moles × molar mass

∴ mass of Na = 1.619 × 10⁻¹¹ mol ×  23 g/mol
                      = 3.72 × 10⁻¹⁰ g


4 0
3 years ago
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