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jekas [21]
2 years ago
12

A security specialist discovers a malicious script on a computer. The script is set to execute if the administrator's account be

comes disabled. What type of malware did the specialist discover
Computers and Technology
1 answer:
levacccp [35]2 years ago
7 0

The security specialist has discovers a malicious script on a computer known as a logic bomb.

<h3>Is logic bomb a type of malware?</h3>

A logic bomb is known to be a form of a malicious program that is set up or ignited if a logical condition is met, such as after a series of transactions have been done, or on a given date.

Therefore, The security specialist has discovers a malicious script on a computer known as a logic bomb.

Learn more about malware from

brainly.com/question/399317

#SPJ1

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Write a program that takes in a positive integer as input, and outputs a string of 1's and 0's representing the integer in binar
Mashcka [7]

Answer:

Following are the code to this question:

def binarynumber(num):#defining a method binarynumber that accepts a parameter num

   x=""#defining a string variable x

   if (num!=0):#defining if condition to check number not equal to 0

       while (num>=1):#defining a loop that check value is grater then equal to one

           if (num %2==0):#defining if condition to check num is even

               x=x+"0" #add string value 0 in num variable

               num=num/2 #divide the value by 2

           else:#defining else block

               x=x+"1"#add string value 1 in num variable

               num=(num-1)/2#first subtract 1 into num variable then divide the value by 2

   else:

       x="0"#assign string value 0 in num variable  

   return "".join(reversed(x))#return value

num = int (input ("Enter any number: "))#defining num variable that input the integer value

print (binarynumber(num))#using print method to call method binarynumber with passing num parameter

Output:

Enter any number: 12

1100

Explanation:

  • In the above python code a method "binarynumber" is declared, in which the "num" variable passes as the parameter inside the method a string variable "x" is declared that stores all converted values.
  • Inside the method and if the block is declared that checks number value is not equal to 0 if this condition is false then it will add string value and reverse its value.
  • Or if the condition is true it defines a while loop that calculates the given number binary digits and returns its value.
  • At the last step, the num variable is declared that inputs the integer value from the user end and calls the method by using the print method.    
6 0
3 years ago
Which data type is also called a binary object?
Andrej [43]
Binary large objects(BLOb):this data type is also called a binary object, and its fields are called binary fields.
7 0
3 years ago
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Which statement is true about wikis? Wikihow is an online dictionary that aims to define words. A wiki cannot be used in an orga
True [87]
The true statement abt Wikis is "<span>Among Wikipedians, editors can grant or remove administrator rights."</span>
8 0
3 years ago
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What does in-private or incognito browsing do?
Aleks04 [339]

All it does it let you browse the internet, but whatever you look up, it isn't put on your browser history.
5 0
3 years ago
Write a function called count_occurrences that takes two strings. The second string should only be one character long. The funct
iVinArrow [24]

Answer:

Here is the Python function:

def count_occurrences (string1 , string2):  # method that takes two strings as parameter and returns how many times second string occurs in first

   count = 0  #counts number of occurrence of string2 in string1

   for word in string1:  #iterates through each word of the string1

       for character in word:  #iterates through each character of each word in string1

           if character == string2:  # checks if the character in string1 is equal to the character of string2

               count = count + 1  #adds 1 to the count of string2 in string1

   return count  #returns number of times the string2 occurs in string1

#in order to check the working of the function add the following lines to the code:    

first_str = input("Enter the first string: ")  #prompts user to enter first string

second_str = input("Enter the second string (one character long): ") #prompts user to enter second string which should be one character long

occurrence = count_occurrences(first_str,second_str)  #calls count_occurrences method by passing both strings to it

print(second_str,"occurs",occurrence,"times in",first_str) #prints how many times the second_str occurs in the first_str on output screen

Explanation:

The program is well explained in the comments added to each statement of the above code. I will explain the program with an example:

Suppose

string1 = "hello world"

string2 = 'l'

So the method count_occurrences() should return how many times l occurs in hello world.

count is used to count the number of occurrences of l in hello world. It is initialized to 0.

The first loop iterates through each word of string1. The first word of string1 is "hello"

The second loop iterates through each character/letter of each word. So the first letter of "hello" word is 'h'.

The if condition if character == string2: checks if the character is equal to string2 i.e. l.

character = "h"

string2 = "l"

The are not equal so the program moves to the next character of word hello which is e. The if condition again evaluates to false because e is not equal to l. So the program moves to the next character of word hello which is l.

This time the if condition evaluates to true because

character = "l"

string2 = "l"

character == string2

l == l

So the if part is executed which has the following statement:

count = count + 1

So the count is added to 1. count was 0 previously. Now

count = 1

Next the program moves to the next character of word hello which is l. This time the if condition evaluates to true because the character l matches with string2. So count is again incremented to 1. count = 2.

Next the program moves to the next character of word hello which is o. The if condition evaluates to false as o does not match with string2 i.e. l. So the count remains 2.

Next the first loop moves to the next word of the string1 = "world". The inner (second) for loop iterates through each character of "world" from "w" to "d" and checks if any character is equal to string2. Only one character is equal to string2 in "world". So count is incremented to 1. Hence count = 3

After the loop ends the statement return count returns the number of times string2 occurs in the string1. So the output is:

l occurs 3 times in hello world  

8 0
3 years ago
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