Given that JKLM is a rhombus and the length of diagonal KM=10 na d JL=24, the perimeter will be found as follows;
the length of one side of the rhombus will be given by Pythagorean theorem, the reason being at the point the diagonals intersect, they form a perpendicular angles;
thus
c^2=a^2+b^2
hence;
c^2=5^2+12^2
c^2=144+25
c^2=169
thus;
c=sqrt169
c=13 units;
thus the perimeter of the rhombus will be:
P=L+L+L+L
P=13+13+13+13
P=52 units
f(x)=40
x=8
so if x=2 it would be 40/8 which is 5
Answer:
$12.49
Step-by-step explanation:
9.99 divided by .8
Answer:
Step-by-step explanation:
Pythagorean theorem,
hypotenuse² = Base² + altitude²
= 8² + 10²
= 64 + 100
= 164
hypotenuse = √164 = 12.8 cm
Answer:
B
Step-by-step explanation:
i hope it helps
#CarryOnLearning
