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wlad13 [49]
4 years ago
8

A(n) __________ is a fast-flowing river of air at the boundary between the troposphere and stratosphere.

Physics
1 answer:
Ivahew [28]4 years ago
7 0
<span>This is the jet stream. This air current flows from west to east along a typically-meandering path that is often used as a predictor of weather conditions. These currents are typically formed from the fact that the equator is warmer than the poles, and this allows the different-density air masses to develop an eastward-moving component.</span>
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wallace and vernonville are 192 miles apart. A car leaves wallace traveling towards vernonville, and another car leaves vernonvi
Anastaziya [24]
 <span>1 hour 36 minutes = 1 36/60 = 1 3/5 = 1.6 hours 

Speed of car leaving wallace be x mph 

Speed of car leaving vernonville will be ( x+10) mph 

1.6 ( x + x+10) = 192

2x + 10 = 120

2x = 110

x = 55

ANSWER Wallace car = 55 mph Vernonville = 65mph 

Therefore, </span><span>the average speeds of both cars are 55 mph for the Wallace car and 65 mph for the Vernonville.


I hope my answer has come to your help. Thank you for posting your question here in Brainly.</span>
3 0
3 years ago
A racing car reaches a speed of 42 m/s. It then begins a uniform negative acceleration, using its parachute and braking system,
NARA [144]

As per the question the initial speed of the car [ u] is 42 m/s.

The car applied its brake and comes to rest after 5.5 second.

The final velocity [v] of the car will be zero.

From the equation of kinematics we know that

                                         v=u+at [ here a stands for acceleration]

                                         0=42 +5.5a

                                         a =\frac{-42}{5.5} m/s^2

                                          a= -7.64 m/s^2

Here a is taken negative as it the car is decelerating uniformly.

We are asked to calculate the stopping distance .

From equation of kinematics we know that

                                              S=ut+\frac{1}{2} at^2  [here S is the distance]

                                                      = 42*5.5 +\frac{1}{2} [-7.64] [5.5]^2 m

                                                       =115.445 m      [ans]  

8 0
3 years ago
A spherical shell rolls without sliding along the floor. The ratio of its rotational kinetic energy (about an axis through its c
True [87]

Answer:

The ratio  is  \frac{RE}{TE}  = \frac{2}{3}

Explanation:

Generally  the Moment of inertia of a spherical object (shell) is mathematically represented as

              I  =  \frac{2}{3} *  m r^2

Where m is  the mass of the spherical object

       and   r is the radius  

Now the the rotational kinetic energy can be mathematically represented as

       RE  = \frac{1}{2}*  I *   w^2

Where  w is the angular velocity which is mathematically represented as

             w =   \frac{v}{r}

=>           w^2  =   [\frac{v}{r}] ^2

So

             RE  = \frac{1}{2}*  [\frac{2}{3} *mr^2] *   [\frac{v}{r} ]^2

            RE  = \frac{1}{3} * mv^2

Generally the transnational  kinetic energy of this motion is  mathematically represented as

                TE = \frac{1}{2} mv^2

So  

      \frac{RE}{TE}  =  \frac{\frac{1}{3}  * mv^2}{\frac{1}{2} * m*v^2}

       \frac{RE}{TE}  = \frac{2}{3}

5 0
3 years ago
To travel at a constant speed,a car engine provides 24 KW of useful powers. The driving force on the car is 600N.AT what speed d
Whitepunk [10]

Answer: D. 40

Explanation:

Power = Force * Velocity

Force = 600N

Power needs to be converted to Watts:

= 24 * 1,000

= 24,000 W

24,000 = 600 * Velocity

Velocity = 24,000/600

= 40 m/s

3 0
3 years ago
The reaction of magnesium ribbon with oxygen.what is the product formed?
zaharov [31]
When oxygen reacts with magnesium thenMgO3 is formed.

Mg +O2----> MgO3
6 0
3 years ago
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