Answer:
total work is = 52450 J
Explanation:
given data
mass = 5000-lb
density = 10 lb/ft
height = 50 ft
solution
as we will treat here cable and ball are separate
and
here work need to lift cable is
w = (10Δy )(9.8 y ) j
and
now summing all segment of cable
so passing limit Δy to 0
so total work need
= 
= ![[49 y^2]^{50}_0](https://tex.z-dn.net/?f=%5B49%20y%5E2%5D%5E%7B50%7D_0)
= 2450J
so lifting 5000 lb wrcking 50 m required additional 5000 + 2450
so total work is = 52450 J
-4.4 ft/s^2
Explanation:
Final Velocity= 35 mph
Starting Velocity= 50 mph
Elapsed Time= 5 seconds
When plugged into formula for Acceleration it is this
True.........All kinds of bad stuff hidden from cops
Answer:
30 seconds
Explanation:
The formula for calculating acceleration is
( final velocity - inital velocity) ÷ time
If we enter the values, it would be (250 - 100) ÷ t = 5m/s^2
Now we need to know 't'
So we rearrange the equation to make t the subject.
(250-100) ÷ 5 = 30s
