Answer:
24s^2, 54s^2, 96s^2
Step-by-step explanation:
Let s represent the initial side length of the cube. Then the area of each face of the cube is A = 6s^2 (recalling that the area of a square of side length s is s^2).
a) Now suppose we double the side length. The total area of the 6 faces of the cube will now be A = 6(2s)^2, or 24s^2 (a 24 times larger surface area),
b) tripled: A = 6(3s)^2 = 54x^2
c) quadrupled? A = 6(4s)^2 = 96s^2
Answer:
25/100 which can be reduced to 1/4
Step-by-step explanation:
there are 25 cents in a quarter
there are 100 cents in a dollar
so the ratio is 25/100 which can be reduced to 1/4
Option C: ∠2 and ∠8
Option E: ∠3 and ∠5
Solution:
Two parallel lines cut by a transversal.
Option A: ∠5 and ∠4
∠4 is not interior of parallel lines.
Hence it is not true.
Option B: ∠6 and ∠5
∠6 is not interior of parallel lines.
Hence it is not true.
Option C: ∠2 and ∠8
∠2 and ∠8 lies in the interior of the parallel lines.
∠2 and ∠8 lies in alternate of the transversal line.
Therefore, ∠2 and ∠8 are alternate interior angles.
Hence it is true.
Option D: ∠8 and ∠1
∠1 is not interior of parallel lines.
Hence it is not true.
Option E: ∠3 and ∠5
∠3 and ∠5 lies in the interior of the parallel lines.
∠3 and ∠5 lies in alternate of the transversal line.
Therefore, ∠3 and ∠5 are alternate interior angles.
Hence it is true.
Therefore ∠2 and ∠8, ∠3 and ∠5 are alternate interior angles.
Answer:
see explanation
Step-by-step explanation:
To determine which ordered pairs satisfy the equation substitute the x coordinate of the point into the right side and if the value obtained equals the y coordinate of the point then it satisfies the equation
(- 1, - 1)
x = - 1 : y = - 4 + 3 = - 1 ⇒ (- 1, - 1) satisfies the equation
(2, 11)
x = 2 : y = 8 + 3 = 11 ⇒ (2, 11) satisfies the equation
(4, 7)
x = 4 : y = 16 + 3 = 19 ≠ 7 ⇒ (4, 7) does not satisfy the equation
(7, 1)
x = 7 : y = 28 + 3 = 31 ≠ 1 ⇒ (7, 1) does not satisfy the equation
Answer:
D. 
Step-by-step explanation:
Given:
Required:
Find its equivalent expression
Solution:
Add both fractions
Thus,
Therefore,
