The triangle on the left has height 24 ft and base 18 ft, and therefore, by the area-of-a-triangle formula A = (1/2)(b)(h), the area of the triangle is
A = (1/2)(24 ft)(18 ft) = 216 ft^2.
The semicircle on the right has radius (18 ft)/2, or 9 ft. Using the area-of-a-semicircle formula A =(pi)(r)^2/2, we find this particular semicircle to have area
A = (pi)(9)^2/2, or approximately 127 ft^2
Adding these two subareas together results in total area
You have to find a common denominator, so you would multiply 3 from the 1/3 by 4 which gets you twelve. And bc you multiplied the 3 you have to multiple the 1 so 1/3 would be 4/12. You would then multiply 4 by 3 and get 12. Then do the same to the one on top. So 1/4 would be 3/12. You then add 3 and 4 and get 7. That’s the numerator, the denominator stays 12. So it would be 7/12
