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fredd [130]
2 years ago
9

3. Order the rational numbers from least to greatest: 0.5, 0, - 1.5, 1, -0.5, -1

Mathematics
1 answer:
harina [27]2 years ago
8 0

Answer:

-1.5,-1,0,0.5,1 is the answer

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Calculate and express your answer in Decimal from 1/2×17
prohojiy [21]

Answer:

8.5

Step-by-step explanation:

6 0
2 years ago
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What is 48% of 72 time 3 divided by 9
devlian [24]
11.52 72×3=216x48÷100÷9= 11.52
8 0
3 years ago
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Tina's aquarium has a capacity of 40 gallons or water. She plans to stock her aquarium with 0.25 inches of fish per quart of cap
Sonbull [250]

Answer:

The number of mollies fishes in the aquarium is 20 .

Step-by-step explanation:

Given as :

The capacity of aquarium = 40 gallons

∵ 1 gallon = 4 quart

∴ 40 gallons = 4 × 40 = 160 quart

Now, According to question

0.25 inches of fish required 1 quart capacity

I.e for 1 quart capacity , 0.25 inches fish

So. for 160 quart capacity , 0.25 × 160 = 40 inches fishes

Now the size of mollies fish = 2 inches

Then ,  number of mollies fish = \dfrac{\textrm total size of fishes}{\textrm size of mollies fish}

I.e Number of mollies fish = \frac{40}{2} = 20

Hence The number of mollies fishes in the aquarium is 20 .   Answer

3 0
2 years ago
I need help with this someone very smart at math this algebra 2
Mrac [35]

Answer:

value if a =

\frac{5}{4}

Step-by-step explanation:

here's the solution :-

=》

\frac{ 2(\sqrt{m})  {}^{3} }{ \sqrt[4]{m} }

=》

\frac{2(m {}^{ \frac{1}{2}} ) {}^{3} }{ {m}^{ \frac{1}{4} } }

=》

\frac{2 {m}^{ \frac{3}{2} }} { {m}^{ \frac{1}{4} } }

=》

2m {}^{ \frac{3}{2}  -  \frac{1}{4} }

=》

2m {}^{ \frac{6 - 1}{4} }

=》

2m {}^{ \frac{5}{4} }

so, a = 5/4

6 0
2 years ago
Brainliest + Points!
LenaWriter [7]
Hey refer to attachment!!!

Draw straight line from 220 (in thousands ) to the plotted line. Draw line parallel to x-axis from point where it touches the plotted line to the y -axis.

It'll automatically meet at 500 which is the answer..

All you need to do is to see the graph carefully.

Hope it helps *_*

3 0
3 years ago
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