She will cover distance in 3 days and 16 hours .the time will be 3:15 am on the fourth day.
Convert 5.9 miles/hour to feet/hour there are 5,280 feet in a mile
total distance covered = 47500
distance = rate x time
now, time = 47500/5280
time = 88 hours
88 hours = 3 Days and 16 Hours.
now the time will be 3 :15 am on the fourth day.
The overall distance the object covers in a given amount of time is its average speed. A scalar value represents the average speed. It has no direction and is indicated by the magnitude.
The distance traveled divided by the time taken is the most popular formula for calculating average speed. The alternative formula is to add the initial and final speeds together, then divide by 2.
Learn more about distance time problems here: -
brainly.com/question/13269893
#SPJ4
They all don’t, they also can have positive charges like LiOH (Lithium Hydroxide)
Explain whether this is a chemical or physical change, and why. does it involve elements, compounds, mixtures, or pure substances?
If the process involves a chemical reaction then surely it is a chemical change where new bonds are being formed from the collision of the reactants.
Describe how many atoms are involved before and after. what do you notice about the number of atoms?
From the balanced chemical reaction, we see that we need 1 mol of N2 gas and 3 mol of H2 in order to form 2 mol of NH3.
Answer:
The answer is A, if im not mistaken
Answer:
<u><em></em></u>
- <u><em>Because the x-intercet of the graph represents volume zero, which indicates the minimum possible temperature or absolute zero.</em></u>
Explanation:
Charle's Law for ideal gases states that, at constant pressure, the <em>temperature</em> and the <em>volume</em> of a sample of gas are protortional.

That means that the graph of the relationship between Temperature, in Kelivn, and Volume is a line, which passes through the origin.
When you work with Temperature in Celsius, and the temperature is placed on the x-axis, the line is shifted to the left 273.15ºC.
Meaning that the Volume at 273.15ºC is zero.
You cannot reach such low temperatures in an experiment, and also, volume zero is not real.
Nevertheless, you can draw the line of best fit and extend it until the x-axis (corresponding to a theoretical volume equal to zero), and read the corresponding temperature.
Subject to the experimental errors, and the fact that the real gases are not ideal, the temperature that you read on the x-axis is the minimum possible temperature (<em>absolute zero</em>) as the minimum possible volume is zero.