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Gnesinka [82]
3 years ago
5

Which substance made up minerals

Chemistry
2 answers:
Alenkasestr [34]3 years ago
4 0

Answer

Chemical element

Explanation:

kari74 [83]3 years ago
3 0

Answer:

chemical elements

Explanation:

sorry if im wrong.

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3 years ago
100 POINTS! HELP ME IF YOU LOVE JESUS!
mr Goodwill [35]
I only got 50 points (which is not 100). :-)

Look at the graph. At 80 °C, about 38 g of solute is able to dissolve, and that’s for ever 100 g of water. That means that for every 150 grams of water, 57 grams of solute can dissolve (38/2 = 19 + 38 = 57 g) at 80 °C. Since 57 g is greater than 55 g, all for he sodium chloride should dissolve in 150 g of water at 80 °C - you can put all of that into a “mathematical explanation”.
4 0
2 years ago
How does a buffer resist change in ph upon addition of a strong acid?
lora16 [44]
Any buffer exists in this equilibrium
 
  HA <=> H^+ + A^-
In a buffer, there is a large reservoir of both the undissociated acid (HA) and its conjugate base (A^-) 

When a strong acid is added, it reacts with the large reservoir of the conjugate base (A^-) forming a salt and water. Since this large reservoir of the conjugate base is used, the ph does not alter drastically, but instead resist the pH change. 

8 0
3 years ago
While a certain isotope decays, it emits photons. What kind of decay is happening?
gizmo_the_mogwai [7]
The correct answer is Gamma decay. It happens after beta and alpha decay because what's left after those two can enter a new process of gamma decay. This releases gamma rays which is a more complex term for the photons that you mentioned before. These rays can be dangerous for humans so care not to get caught in them.
6 0
3 years ago
Read 2 more answers
Calculate the molar solubility of CaF2 in a 0.25 m solution of NaF(aq).
Kipish [7]

Answer:

6.4 × 10^-10 M

Explanation:

The molar solubility of the ions in a compound can be calculated from the Ksp (solubility constant).

CaF2 will dissociate as follows:

CaF2 ⇌Ca2+ + 2F-

1 mole of Calcium ion (x)

2 moles of fluorine ion (2x)

NaF will also dissociate as follows:

NaF ⇌ Na+ + F-

Where Na+ = 0.25M

F- = 0.25M

The total concentration of fluoride ion in the solution is (2x + 0.25M), however, due to common ion effect i.e. 2x<0.25, 2x can be neglected. This means that concentration of fluoride ion will be 0.25M

Ksp = {Ca2+}{F-}^2

Ksp = {x}{0.25}^2

4.0 × 10^-11 = 0.25^2 × x

4.0 × 10^-11 = 0.0625x

x = 4.0 × 10^-11 ÷ 6.25 × 10^-2

x = 4/6.25 × 10^ (-11+2)

x = 0.64 × 10^-9

x = 6.4 × 10^-10

Therefore, the molar solubility of CaF2 in NaF solution is 6.4 × 10^-10M

8 0
3 years ago
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