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3 years ago

Latitude affects climate by?

Chemistry

2 answers:

emmasim [6.3K]3 years ago

4 0

Answer: A. Farther from the equator, the colder it is.

Explanation: its the right answer

attashe74 [19]3 years ago

3 0

The answer to your question is A.

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How many grams of chlorine are required to react with 5.00 moles of sodium to produce sodium chlorine?

Oduvanchick [21]

Answer:

2.5 mol Cl2 will react with 5 mol Na.

Explanation:

5 0

3 years ago

Read 2 more answers

Which of the following is an empirical formula? a) H2O2 b) H2O c) C2H2 d) C4H8

Alex_Xolod [135]

Carrot carrot carrot carrot

3 0

3 years ago

A saturated solution is made by dissolving 0.327 g of a polypeptide (a substance formed by joining together in a chainlike fashi

faust18 [17]

Answer: The approximate molecular mass of the polypeptide is 856 g/mol

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=iMRT$

Or,

$\pi=i\times \frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution in L)}}\times RT$

where,

$\pi$ = osmotic pressure of the solution = 4.19 torr

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (polypeptide) = 0.327 g

Volume of solution = 1.70 L

R = Gas constant = $62.364\text{ L.torr }mol^{-1}K^{-1}$

T = temperature of the solution = $26^oC=[273+26]K=299K$

Putting values in above equation, we get:

$4.19torr=1\times \frac{0.327}{\text{Molar mass of solute}\times 1.70}\times 62.364\text{ L.mmHg }mol^{-1}K^{-1}\times 299K\\\\\text{molar mass of solute}=856g/mol$

Hence, the molar mass of the polypeptide is 856 g/mol

8 0

3 years ago

Predict the products of this reaction: H2 + Cl2 →

Readme [11.4K]

Answer:

2HCl is the product of this reaction 2 is added in order to balance the reaction

8 0

3 years ago

Draw the structure of a compound with the molecular formula C9H10O2 that exhibits the following spectral data. (a) IR: 3005 cm-1

Nikitich [7]

Answer:

The answer is 3-Phenylpropanoic acid (see attached structure)

Explanation:

From spectral data:

3005 cm-1 ⇒ carboxylic acid (broad band)

1670 cm-1 ⇒ C=C

1603 cm-1 ⇒ Aromatic C-C bond

H NMR frequency at 2.6 ppm, singlet, ⇒ OH with no surrounding protons, possible deshielding (clearer investigation of spectrum would be expedient).

Hence, our C9H10O2 compound has an aromatic ring and carboxylic acid group attached to it.

7 0

3 years ago