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Wittaler [7]
3 years ago
15

What is Loschmidt’s number? How is it related to Avogadro’s number?

Chemistry
1 answer:
maxonik [38]3 years ago
5 0
1. Loschmidt’s number also called as Loschmidt’s constant, n₀ is the number of particles of an ideal gas in a given volume (m³). The  unit is m⁻³. At standard pressure (1 atm) and temperature (0 °C) the value of <span>Loschmidt’s number is 2.686 x 10</span>²⁵ m⁻³.

2. 
Loschmidt’s number,n₀ can be expressed as,
        n₀ =  \frac{P}{kT}
where P is the pressure of the gas, K is the Boltzmann constant and T is the <span>thermodynamic temperature.

Since, k = R/NA (where R is the universal gas constant and NA is the Avogadro constant)
</span>n₀ = \frac{P}{(R/NA)T}
n₀ = \frac{PNA}{RT}

Hence, n₀ α NA

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<h3>Answer:</h3>

3.67 mol Al

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

2.21 × 10²⁴ atoms Al

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 2.21 \cdot 10^{24} \ atoms \ Al(\frac{1 \ mol \ Al}{6.022 \cdot 10^{23} \ atoms \ Al})
  2. Divide:                              \displaystyle 3.66988 \ mol \ Al

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

3.66988 mol Al ≈ 3.67 mol Al

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