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lisov135 [29]
3 years ago
7

PLEASE HELP! How does one determine how much of a molecule is produced in a reaction?

Chemistry
1 answer:
kozerog [31]3 years ago
7 0
I believe the answer is C !
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Which two cell components deal with the same kind of chemical substance ( lipid, protein, enzyme, and so on)
geniusboy [140]

Answer:

Cell membrane and cytoplasm

Explanation:

Cell membrane is the layer that surronds the cell and it is made up of lipids and proteins. It is made up of a kind of fatty acids based lipids i.e phospholipids and sterols.

Cytoplasm is a thick fluid that is found in the cell membranes. It acts as buffer and protect cells organelles and DNA from damage. It is made up of water, p, lipids, proteins, inorganic salts, nucleic acids.

6 0
3 years ago
Iodine 131, cesium 137, and strontium 90 are all considered isotopes. What are isotopes?
Nitella [24]

Answer:

Isotopes are variants of an element, where the number of neutrons is different but its number of protons stay the same.

Explanation:

If the number of protons had changed then it would just be a different element.

Electron number changing simply adds charge to the atom, and doesn't change it or anything.

PLS GIVE BRAINLIEST

3 0
3 years ago
Read 2 more answers
Balance the equation for this reaction:<br> _ FeCl3 + KSCN --<br> --&gt; _ KCI + Fe(SCN)3
kykrilka [37]

Explanation:

FeCl3 + <u>3</u> KSCN ➡ <u>3</u> KCl + Fe(SCN)3

Hope it helps

3 0
3 years ago
If you start with 0.30 m mn2 , at what ph will the free mn2 concentration be equal to 4.6 x 10-11 m?
aksik [14]

If you start with 0.30 m Mn₂ , at 12.5 pH, free Mn₂ concentration be equal to 4.6 x 10⁻¹¹ m

Initial molarity of Mn₂ = 0.30 M

Final molarity of Mn₂ = 4.6 x 10⁻¹¹

pH = ?

Ksp [Mn(OH)₂] = 4.6 x 10⁻¹⁴ (standard value)

Write the ionic equation

    Mn(OH)₂   →    Mn⁺² + 2OH⁻

    [Mn⁺²] = 4.6 x 10⁻¹¹

We will calculate the concentration of OH⁻ by using Ksp expression

    Ksp = [Mn⁺²][OH-]²

    [Mn⁺²][OH⁻]² = 4.6 x 10⁻¹⁴

    [OH⁻]² = 4.6 x 10⁻¹⁴ / 4.6 x 10⁻¹¹

    [OH⁻]² = 10⁻³

    [OH⁻] = (10⁻³)¹⁽²

    [OH⁻] = 0.0316 M

Calculate the pOH

    pOH = -log [OH⁻]

    pOH =  -log [0.0316]

    pOH = 1.5

Now calculate pH

   pH = 14 - pOH

   pH = 14 - 1.5

   pH = 12.5

You can also learn about molarity from the following question:

brainly.com/question/14782315

#SPJ4

7 0
1 year ago
Helppppppppppp please
valentinak56 [21]
Your answer would have to be #3
4 0
3 years ago
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