Answer:
A
Step-by-step explanation:
Answer: (7.27%, 7.55%)
Step-by-step explanation:
As per given , we have
Sample size : n= 392
Sample mean : 

Critical two-tailed z-value for 95% confidence = 
Required confidence interval would be :

Hence, the required 95% confidence interval for the mean percentage share of billing volume from network television for the population of all U.S. advertising agencies : (7.27%, 7.55%)
The answer is either number or two I suppose.
Answer:
(15 , 7)
Step-by-step explanation:
(-3+0+3+6+9 , 11+-7+-3+1+5)
(15,7)

$=(a^2-10a)-(b^2+6b) +16$
$=[(a^2-2(5)a+25)-25]-[(b^2+2(3)b+9)-9]+16$
$=(a-5)^2-25-(b+3)^2+9+16$
$=(a-5)^2-(b+3)^2$