Answer:
x = 12
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
g(x) = 1/2x - 11
g(x) = -5
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute: -5 = 1/2x - 11
- Isolate <em>x</em> term: 6 = 1/2x
- Isolate <em>x</em>: 12 = x
- Rewrite: x = 12
Answer:
h = 12
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
Step-by-step explanation:
<u>Step 1: Define equation</u>
0.75h + 3 = 12
<u>Step 2: Solve for </u><em><u>h</u></em>
- Subtract 3 on both sides: 0.75h = 9
- Divide 0.75 on both sides: h = 12
<u>Step 3: Check</u>
<em>Plug in h into the original equation to verify it's a solution.</em>
- Substitute in <em>h</em>: 0.75(12) + 3 = 12
- Multiply: 9 + 3 = 12
- Add: 12 = 12
Here we see that 12 does indeed equal 12.
∴ h = 12 is a solution of the equation.
Answer:
3.1 gallons
Step-by-step explanation:
To solve this, we need to figure out how many gallons of gas go into 72 miles. We know 23 miles is equal to one gallon of gas, and given that the ratio of miles to gas stays the same, we can say that
miles of gas / gallons = miles of gas / gallons
23 miles / 1 gallon = 72 miles / gallons needed to go to Bob's mother's house
If we write the gallons needed to go to Bob's mother's house as g, we can say
23 miles / 1 gallon = 72 miles/g
multiply both sides by 1 gallon to remove a denominator
23 miles = 72 miles * 1 gallon /g
multiply both sides by g to remove the other denominator
23 miles * g = 72 miles * 1 gallon
divide both sides by 23 miles to isolate the g
g = 72 miles * 1 gallon/23 miles
= 72 / 23 gallons
≈ 3.1 gallons
Answer:
this means that there is an exponent missing EX{5^3
Step-by-step explanation:
