For the reaction:
3A +5B--->12C
Here 3 moles of A are reacting with 5 moles of B to produce 12 moles of C.
so, 1 mole of A will produce = 12÷3 moles of C
= 4 moles of C
so 2 moles of A will produce = 4×2 moles of C
= 8 moles of C
so, 2 moles of A are reacting with excess of B to produce 8 moles of C.
so , the answer is 2 moles of A are reacting with excess of B to produce 8 moles of C.
Answer:
0.169 mole of Al
Explanation:
We'll begin by by calculating the number of mole in 45 gof AlBr₃. This can be obtained as follow:
Mass of AlBr₃ = 45 g
Molar mass of AlBr₃ = 27 + (3×80)
= 27 + 240
= 267 g/mol
Mole of AlBr₃ =?
Mole = mass /molar mass
Mole of AlBr₃ = 45 / 267
Mole of AlBr₃ = 0.169 mole
Finally, we shall determine the number of mole of Al needed to produce 45 g (i.e 0.169 mole) of AlBr₃. This can be obtained as illustrated below:
2Al + 3Br₂ —> 2AlBr₃
From the balanced equation above,
2 moles of Al reacted to produce 2 moles of AlBr₃.
Therefore, 0.169 mole of Al will also react to produce 0.169 mole of AlBr₃.
Thus, 0.169 mole of Al is needed for the reaction.
Covalent compounds share with each other, whilst Ionic compounds take from each other.
Covalent compounds are composed of 2 or more NONMETALS.
So, it would be CO, since the rest of the compounds contain metals in them.
<h2>Phenocrysts and Porphyritic texture
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Explanation:
- The early formed crystals are of phenocrysts and the texture of these crystals is porphyritic texture.
- This crystallization occurs when early-forming plagioclase crystals which are rich in calcium start coating with plagioclase crystals which are rich in sodium.
- On cooling, the magma is then processed in a volcanic eruption, after the eruption the liquid which is left behind will start cooling and forms a porphyritic texture.
A periodic table is tabular arrangement of the chemical elements, ordered by their atomic number,electronic configuration and recurring chemical properties. carbon is in group 14 and period two. The atomic mass of carbon from periodic table is 12.01 g/mole
