Answer:
1.07×10²¹ molecules are needed to sound the alarm
Explanation:
Let's convert the mass of CO to moles, to determine the amount of molecules.
0.05 g . 1 mol / 28 g = 1.78×10⁻³ moles
Now we can determine the number of molecules with the NA
1 mol has 6.02×10²³ molecules
1.78×10⁻³ moles may have (1.78×10⁻³ . 6.02×10²³) / 1 = 1.07×10²¹ molecules
Answer:
The sample will be heated to 808.5 Kelvin
Explanation:
Step 1: Data given
Volume before heating = 2.00L
Temperature before heating = 35.0°C = 308 K
Volume after heating = 5.25 L
Pressure is constant
Step 2: Calculate temperature
V1 / T1 = V2 /T2
⇒ V1 = the initial volume = 2.00 L
⇒ T1 = the initial temperature = 308 K
⇒ V2 = the final volume = 5.25 L
⇒ T2 = The final temperature = TO BE DETERMINED
2.00L / 308.0 = 5.25L / T2
T2 = 5.25/(2.00/308.0)
T2 = 808.5 K
The sample will be heated to 808.5 Kelvin
Answer:
moles react.
Explanation:
In a chemical reaction equation, we know that chemical species react in moles. It is actually the moles of the individual chemical species that participate in a chemical reaction and not the masses of those species.
In solving stoichiometric problems, it is mandatory to use moles as a conversion factor in calculating the mass of product formed or the mass of reactant consumed. We often read off the number of moles that reacted from the balanced reaction equation and then convert the reacting mass of species given to the number of moles of that specie that actually participated in the reaction in order to obtain any required information from a reaction.
Answer:
Low density
Explanation:
The answer to this question is low density as Gases in general have low densities as their particles are very far apart. Their inter-molecular spaces are actually large. And The number of molecules per unit volume in a gas are small when we put them in comparisons with solids and liquids. That is why they have low densities.
I hope this answers your question.
Answer:
1279 °C
Explanation:
Data Given:
Amount of Heat absorb = 5.82 x 10³ KJ
Convert KJ to J
1 KJ = 1000 J
5.82 x 10³ KJ = 5.82 x 10³ x 1000 = 5.82 x10⁶ J
mass of sample = 8.92 Kg
Convert Kg to g
1 kg = 1000 g
8.92 Kg = 8.92 x 1000 = 8920 g
Cs of steel = 0.51 J/g °C
change in temperature = ?
Solution:
Formula used
Q = Cs.m.ΔT
rearrange the above equation to calculate the mass of steel sample
ΔT = Q / Cs.m .... . . . . . (1)
Where:
Q = amount of heat
Cs = specific heat of steel = 0.51 J/g °C
m = mass
ΔT = Change in temperature
Put values in above equation 1
ΔT = 5.82 x10⁶ J / 0.51 (J/g °C) x 8920 g
ΔT = 5.82 x10⁶ J /4549.2 (J/°C)
ΔT = 1279 °C
So,
change in temperature = 1279 °C
