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barxatty [35]
2 years ago
8

It requires 2,500 joules to raise a certain amount of water (c = 4.186 j/g°c) from 20.0°c to 60.0°c. what is the mass of the wat

er that is being heated? 15 g 40 g 63 g 80 g
Chemistry
1 answer:
Bogdan [553]2 years ago
5 0

Answer:

15 grams of water will absorb 2,500 Joules  in going from 20.0 to 60.0 C.

Explanation:

The heat involved in raising a mass (m) of a substance with a specific heat (c) from one temperature to another (Delta T) is given by:

Heat = mc(Delta T)

2,500 Joules = m*(4.186J/gC)*(60C-20C)

2,500 Joules = m*(4.186J/gC)*(40C)

2,500 Joules = m*(4.186J/gC)*(40C)

m = (2,500J)/(4.186*40J/g)

m = 14.93 grams

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Answer : The mass of silver chlorate will be 2.654 grams.

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First we have to calculate the moles of oxygen gas at STP.

As, 22.4 L volume of oxygen gas present in 1 mole of oxygen gas

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Now we have to calculate the moles of silver chlorate.

From the balanced chemical reaction, we conclude that

As, 3 moles of oxygen produced from 2 moles of silver chlorate

So, 0.0208 moles of oxygen produced from \frac{2}{3}\times 0.0208=0.01387 moles of silver chlorate

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\text{Mass of }AgClO_3=\text{Moles of }AgClO_3\times \text{Molar mass of }AgClO_3

Molar mass of silver chlorate = 191.32 g/mole

\text{Mass of }AgClO_3=0.01387mole\times 191.32g/mole=2.654g

Therefore, the mass of silver chlorate will be 2.654 grams.

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