This problem is providing us with the mass of hydrochloric acid and the volume of solution and asks for the pH of the resulting solution, which turns out to be 1.477.
<h3>pH calculations</h3>
In chemistry, one can calculate the pH of a solution by firstly obtaining its molarity as the division of the moles of solute by the liters of solution, so in this case for HCl we have:
Next, due to the fact that hydrochloric acid is a strong acid, we realize its concentration is nearly the same to the released hydrogen ions to the solution upon ionization. Thereby, the resulting pH is:
Which conserves as much decimals as significant figures in the molarity.
Learn more about pH calculations: brainly.com/question/1195974
Use the equation d=m/v
your mass or "m" is 78 g
your volume or "v" is 60mL
if you plug those values into the equation it will look like this:
d=78/60
d=1.3g/mL should be what you come up with
A reaction in which bonds are created is usually associated with the Release of energy.
What are the various types of bonds?
There are three sorts of bonds:
1. Electrovalent or electrovalent bond
2. chemical bond
3. dative bond
Electrovalent or electrovalent bond are formed when one or more electrons are transferred from one atom to another.
Covalent bonds are formed when the atoms during a molecule share an equal number of electrons.
A dative bond is one in which both electrons in a shared pair come from the same atom.
Now, atoms tend to stabilize once they form chemical bonds, releasing energy within the process. Energy is released because there's a higher level of stability associated with a low energy level.
Hence, a reaction in which bonds are created is usually associated with the release of energy.
To know more about chemical bonds go to the given link:
brainly.com/question/20584851
#SPJ4
Answer:
<em>Hydrogen.</em>
Explanation:
You've probably seen "
" which is the formula for water. It means that there's 2 hydrogen atoms, and one oxygen atom, in one molecule of water.
<em>Hope this helps! Feel free to mark me Brainliest if you feel this helped. :)</em>
