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3 years ago

What might two Group 16 non metals likely form?

1 answer:

7 0

When the compound is composed of two non-metals, the the bond that joins them together is called covlent bond. Otherwise, when the compound is composed of a metal and a non-metal then the bond existing between them is called ionic bond. Answer then to this problem is A. covalent bond

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Elements x and y form 2 binary compounds. In the first 14.0 g of x combines with 3.0 g of y. In the second, 7.00 g of x combine

Roman55 [17]

second compound

Let molar mass of x is = X

Let molar mass of y is = Y

Moles of x in second compound = Mass / molar mass = 7 / X

Moles of y in second compound = Mass / molar mass = 4.5 / Y

For second compound

7 / X : 4.5/ Y = 1:1

Therefore

X / Y = 7/4.5

Y / X = 4.5/ 7

The mass of x in first compound = 14g

moles of x in first compound = 14/X

Mass of y in first compound = 3

moles of y in first compound = 3 / Y

14 / X : 3/ Y = 14Y / 3X = 14 X 4.5 / 3 X 7 = 3 :1

Thus molar ratio in first compound = moles of x / Moles of y = 3:2

Formula = x3y

6 0

2 years ago

When a rotting log was turned over, pill bugs, termites , ants , fungi , and earthworms were living there. the termites represen

labwork [276]

D. an abiotic factor

4 0

3 years ago

Consider the following equilibrium: H2CO3+H2O = H3O+HCO3^-1. What is the correct equilibrium expression?

mylen [45]

Equilibrium expression is $Keq = \frac{[H3O+][HCO3^-]}{[H2CO3]}\\$

<u>Explanation:</u>

Equilibrium expression is denoted by Keq.

Keq is the equilibrium constant that is defined as the ratio of concentration of products to the concentration of reactants each raised to the power its stoichiometric coefficients.

Example -

aA + bB = cC + dD

So, Keq = conc of product/ conc of reactant

$Keq = \frac{[C]^c [D]^d}{[A]^a [B]^b}$

So from the equation, H₂CO₃+H₂O = H₃O+HCO₃⁻¹

$Keq = \frac{[H3O^+]^1 [HCO3^-]^1}{[H2CO3]^1 [H2O]^1}$

The concentration of pure solid and liquid is considered as 1. Therefore, concentration of H2O is 1.

Thus,

$Keq = \frac{[H3O+][HCO3^-]}{[H2CO3]}\\$

Therefore, Equilibrium expression is $Keq = \frac{[H3O+][HCO3^-]}{[H2CO3]}\\$

4 0

2 years ago

Name the two molecules Nн нннн

arlik [135]

Answer:

1: C5H12

2:C5H11

Explanation:

nakqkchlqosnx

4 0

2 years ago

HELP ASAP PLEASE PLEASE PLEASE Complete and balance the following reaction. Note that Cr forms +3 in the product. ____ Sn(NO3)2

Rzqust [24]

Answer:

Explanation:

3Sn(NO3)2 (aq) + 2Cr(s) → 2Cr(NO3)3(aq ) + 3Sn(S )

5 0

3 years ago