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svet-max [94.6K]
3 years ago
14

What might two Group 16 non metals likely form?

Chemistry
1 answer:
just olya [345]3 years ago
7 0
When the compound is composed of two non-metals, the the bond that joins them together is called covlent bond. Otherwise, when the compound is composed of a metal and a non-metal then the bond existing between them is called ionic bond. Answer then to this problem is A. covalent bond
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Equation Given : Al^(3+) + Na3PO4 ==> 3Na^+ + AlPO4
Helga [31]

1 mols of Aluminium ion forms 1 mol aluminium phosphate

Molar mass of AlPO_4

  • 27+31+16(4)
  • 58+48
  • 106u

Moles of AlPO_4

  • 61µg/106
  • 0.000061/106
  • 5.75×10^{-7}
  • 57.5µmol

Moles of Al3+=57.5µmol

3 0
2 years ago
A chemistry student needs to standardize a fresh solution of sodium hydroxide. She carefully weighs out 192.mg of oxalic acid H2
kap26 [50]

Answer:

The molarity of the NaOH solution is 0.076 M

Explanation:

Step 1: Data given

Mass of oxalic acid = 192 mg = 0.192 grams

volume = 250 mL = 0.250 L

Molar mass oxalic acid = 90.03 g/mol

Step 2: The balanced equation

H2C2O4 + 2NaOH → Na2C2O4 + H2O

Step 3: Calculate moles of oxalic acid

Moles oxalic acid = 0.192 grams / 90.03 g/mol

Moles oxalic acid = 0.00213 moles

Step 4: Calculate molarity of oxalic acid

Molarity = Moles / volume

Molarity = 0.00213 moles / 0.250 L

Molarity = 0.00852 M

Step 5: Calculate Molarity of NaOH

2 Ca*Va = Cb*Vb

with Ca = Molarity of oxalic acid = 0.00852 M

with Va = volume of oxalic acid = 0.250 L

with Cb = Molarity of NaOH = TO BE DETERMINED

with Vb = volume of 0.0558 L

Cb = (2*0.00852 * 0.25) / 0.0558

Cb = 0.076 M

The molarity of the NaOH solution is 0.076 M

4 0
3 years ago
Calculate the vapor pressure at 25 ?c of hexane above the solution. the vapor pressure of pure hexane at 25 ?c is 151 torr.
Studentka2010 [4]
One of the many ways in order to solve for the vapor pressure of pure components at a given temperature is through the Antoine's equation which is written below,
                                    P = 10^(A - B/C+T)
where A, B, and C are constants and T is the temperature in °C and P is the vapor pressure in mm Hg. 
For hexane,
                             A = 7.01
                             B = 1246.33
                             C = 232.988

Substituting the known values,
                            P = 10^(7.01 - 1246.33/232.988+25)
                             <em> P = 151.199 mm Hg</em>
8 0
3 years ago
Atomic mass of 14.01 amu
OleMash [197]
What is the element with 7 protons?  They probably also have 7 neutrons.  Just a ball park figure guess.
7 0
3 years ago
Iron-59 is a beta emitter with a half-life of 44.5 days. If a sample initially contains 180 mg of iron-59, how much iron-59 is l
Jobisdone [24]

Answer:

2.79 mg iron-59 is left in the sample after 267 days.

Explanation:

Given that:

Half life = 44.5 days

t_{1/2}=\frac {ln\ 2}{k}

Where, k is rate constant

So,  

k=\frac {ln\ 2}{t_{1/2}}

k=\frac {ln\ 2}{44.5}\ days^{-1}

The rate constant, k = 0.0156 days⁻¹

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration  = 180 mg

Time = 267 days

So,  

[A_t]=180\ mg\times e^{-0.0156\times 267}

[A_t]=180\times e^{-0.0156\times 267}\ mg

[A_t]=2.79\ mg

<u>2.79 mg iron-59 is left in the sample after 267 days.</u>

5 0
3 years ago
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