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3 years ago

How many liters are in a .00813M solution that contains 1.55 g of KBr?

Chemistry

1 answer:

Sloan [31]3 years ago

5 0

Answer:

1.602 L (or) 1602 mL

Explanation:

Molarity is the amount of solute dissolved per unit volume of solution. It is expressed as,

Molarity = Moles / Volume of Solution ----- (1)

Rearranging above equation for volume,

Volume of solution = Moles / Molarity -------(2)

Data Given;

Molarity = 0.00813 mol.L⁻¹

Mass = 1.55 g

First calculate Moles for given mass as,

Moles = Mass / M.mass

Moles = 1.55 g / 119.002 g.mol⁻¹

Moles = 0.0130 mol

Now, putting value of Moles and Molarity in eq. 2,

Volume of solution = 0.0130 mol / 0.00813 mol.L⁻¹

Volume of solution = 1.60 L

or,

Volume of solution = 1602 mL

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PLS HELP STOICHIOMETRY/CHEM!!!

Mariulka [41]

The molecular formula of the compound that we are required to find is the compound C4H8O8

<h3>What is empirical formula?</h3>

The empirical formula of a compound is a formula that shows the ratio of each atom present in the compound. We will start by dividing each mass with the relative atomic mass of the atom.

Carbon - 48.38 g/12 Hydrogen - 6.74 g/1 Oxygen - 53.5 g/16

Carbon - 4 Hydrogen - 6.74 Oxygen - 8.9

Dividing through by the lowest ratio;

Carbon - 4/4 Hydrogen - 6.74/4 Oxygen 8.9/4

Carbon 1 Hydrogen 2 Oxygen 2

The empirical formula is CH2O2.

To obtain the molecular formula; brainly.com/question/11588623

[12 + 2 + 32]n = 180

n = 180/[12 + 2 + 32]

n =4

The compound C4H8O8

Learn more about empirical formula:

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3 years ago

The painkiller, Advil® contains the active ingredient ibuprofen (IB), which has a pKb of

denis23 [38]

This problem is providing the basic dissociation constant of ibuprofen (IB) as 5.20, its pH as 8.20 and is requiring the equilibrium concentration of the aforementioned drug by giving the chemical equation at equilibrium it takes place. The obtained result turned out to be D) 4.0 × 10−7 M, according to the following work:

First of all, we set up an equilibrium expression for the given chemical equation at equilibrium, in which water is omitted for it is liquid and just aqueous species are allowed to be included:

$Kb=\frac{[IBH^+][OH^-]}{[IB]}$

Next, we calculate the concentration of hydroxide ions and the Kb due to the fact that both the pH and pKb were given:

$pOH=14-8.20=5.80$

$[OH^-]=10^{-5.8}=1.585x10^{-6}M$

$Kb=10^{-5.20}=6.31x10^{-6}$

Then, since the concentration of these ions equal that of the conjugated acid of the ibuprofen (IBH⁺), we can plug in these and the Kb to obtain:

$6.31x10^{-6}=\frac{(1.585x10^{-6})(1.585x10^{-6})}{[IB]}$

Finally, we solve for the equilibrium concentration of ibuprofen:

$[IB]=\frac{(1.585x10^{-6})(1.585x10^{-6})}{6.31x10^{-6}}=4.0x10^{-7}$

Learn more:

(Weak base equilibrium calculation) brainly.com/question/9426156

4 0

3 years ago

The generic metal a forms an insoluble salt ab(s) and a complex ac5(aq). the equilibrium concentrations in a solution of ac5 wer

Leno4ka [110]

Assuming that the reaction from A and C to AC5 is only one-step (or an elementary reaction) with a balanced chemical reaction of:

A + 5 C ---> AC5

Therefore the formation constant can be easily calculated using the following formula for formation constant:

Kf = product of products concentrations / product of reactants concentration

Kf = [AC5] / [A] [C]^5

---> Any coefficient from the balanced chemical reaction becomes a power in the formula

Substituting the given values into the equation:

Kf = 0.100 M / (0.100 M) (0.0110 M)^5

Kf = 6,209,213,231

or in simpler terms

Kf = 6.21 * 10^9 (ANSWER)

3 0

4 years ago

32P can be used to make any nucleotide (A, C, G, or T) radioactive. Which of the following explains why this is true?

xxMikexx [17]

B. The answer is: All nucleotides have a phosphorus atom that can be replaced with 32P.

Nucleotides contain a nitrogenous base, a five-carbon sugar, and, at least, one phosphate group. Exactly that phosphate group in the nucleotide has the phosphorus atom. Therefore, the phosphorus atom in the nucleotide can be replaced with radioactive phosphorus-32 (32P).

3 0

3 years ago

Which pair of samples contains the same number of oxygen atoms in each compound?0.20 mol Ba(OH)2 and 0.20 mol H2SO40.20 mol Br2O

Whitepunk [10]

Answer:

0.20 mol Br2O and 0.20 mol HBrO have the same number of oxygen atoms

Explanation:

0.20 mol Ba(OH)2 and 0.20 mol H2SO4

In Ba(OH)2 there are 2 moles of O atoms in every mol of Ba(OH)2.

Number of O atoms in 0.20 moles Ba(OH)2 = 2*0.20 = 0.40 moles O atom

In H2SO4 there are 4 moles of O atoms for every mol of H2SO4.

Number of O atoms in 0.20 moles H2SO4 = 4*0.20 = 0.80 moles O atom

⇒ 0.20 mol Ba(OH)2 and 0.20 mol H2SO4 do not have the same number of oxygen atoms.

0.20 mol Br2O and 0.20 mol HBrO

In Br2O there is 1 mol of O atoms in every mol Br2O

Number of O atoms in 0.20 moles Br2O = 0.20*1 = 0.20 moles O atom

In HBrO there is 1 mol of O atom in every mol HBrO

Number of O atoms in 0.20 moles HBrO = 0.20 *1 = 0.20 moles O atom

⇒ in 0.20 moles Br2O and 0.20 moles HBrO we have the same number of oxygen atoms

0.20 moles of Oygen contains: = 0.20 * 6.022*10^23 = 1.2 *10^23 O atoms

0.10 mol Fe2O3 and 0.50 mol BaO

In Fe2O3 there are 3 moles of O atoms in every mol of Fe2O3

Number of O atoms in 0.10 moles Fe2O3 = 0.10 * 3 = 0.30 moles O atom

In BaO there is 1 mol of O atoms in every mol BaO

Number of O atoms in 0.50 mol BaO = 1*0.50 = 0.50 moles O atom

⇒ 0.10 mol Fe2O3 and 0.50 mol BaO do not have the same number of oxygen atoms.

0.10 mol Na2O and 0.10 mol Na2SO4

In Na2O there is 1 mol of O atoms in every mol of Na2O

Number of O atoms in 0.10 mol Na2O = 1*0.10 = 0.10 moles O atom

In Na2sO4 there are 4 moles of O atoms in every mol of Na2SO4

Number of O atoms in 0.10 mol Na2SO4 = 4*0.10 = 0.40 moles O atom

⇒ 0.10 mol Na2O and 0.10 mol Na2SO4 do not have the same number of oxygen atoms.

4 0

4 years ago