A radio telescope detects an incoming radio wave which has a power of 1.00 x 10-24 W. If this signal creates a potential of 1.00

Question

2 years ago

5

nV in the radio receiver, how many electrons move through the receiver circuit per second

1 answer:

soldier1979 [14.2K] · Answer 1 · 2023-06-29T09:09:55+03:00

Answer:

Therefore, the number of electrons moving through the receiver circuit per second is 6250 electrons/s.

Explanation:

Given:

Power of radio wave, P = 1 × 10⁻²⁴ W

Potential of signal, V = 1 × 10⁻⁹ V

Solution:

Consider the number of electrons flowing through the receiver circuit per second be 'n'.

The current flowing through the circuit will be:

I = P/V

= (1 × 10⁻²⁴ W)/(1 × 10⁻⁹ V)

= 1 × 10⁻¹⁵ A

Then, the number of electrons moving through the receiver circuit can be calculated as:

ne = I

where, e is charge on an electron

I is current flowing through the circuit

Applying values in above equation we get:

n(1.6×10⁻¹⁹ C) = (1 × 10⁻¹⁵ A)

n = (1 × 10⁻¹⁵ A)/(1.6×10⁻¹⁹ C)

n = 6250 electrons/s

Therefore, the number of electrons moving through the receiver circuit per second is 6250 electrons/s.

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