Question

A radio telescope detects an incoming radio wave which has a power of 1.00 x 10-24 W. If this signal creates a potential of 1.00 nV in the radio receiver, how many electrons move through the receiver circuit per second

Answer 1

Answer:

Therefore, the number of electrons moving through the receiver circuit per second is 6250 electrons/s.

Explanation:

Given:

Power of radio wave, P = 1 × 10⁻²⁴ W

Potential of signal, V = 1 × 10⁻⁹ V

Solution:

Consider the number of electrons flowing through the receiver circuit per second be 'n'.

The current flowing through the circuit will be:

I = P/V

 = (1 × 10⁻²⁴ W)/(1 × 10⁻⁹ V)

 = 1 × 10⁻¹⁵ A

Then, the number of electrons moving through the receiver circuit can be  calculated as:

ne = I

where, e is charge on an electron

            I is current flowing through the circuit

Applying values in above equation we get:

n(1.6×10⁻¹⁹ C) = (1 × 10⁻¹⁵ A)

n = (1 × 10⁻¹⁵ A)/(1.6×10⁻¹⁹ C)

n = 6250 electrons/s

Therefore, the number of electrons moving through the receiver circuit per second is 6250 electrons/s.

Learn more about electron flow here:

brainly.com/question/6531580

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