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Dominik [7]
3 years ago
12

Explain how competition between organisms affects the availability of resources in an area.

Physics
1 answer:
Fynjy0 [20]3 years ago
7 0

Answer:

Completion between two organism is when they fight over resources inadvertently causing the use and destruction of recourses making it more scares. if they don't adapt they die out.

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DESPERATE WILL GIVE BRAINLIST AND THANKS
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Explanation:

Human body, the physical substance of the human organism, composed of living cells and extracellular materials and organized into tissues, organs, and systems.

https://www.britannica.com › science

human body | Organs, Systems, Structure, Diagram, & Facts |

6 0
3 years ago
Which choice has the least thermal energy?
natulia [17]
It’s A lolololololol
7 0
3 years ago
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A house is maintained at 1 atm and 24°C. Outdoor air at 5.5°C infiltrates into the house through the cracks and warm air inside
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Answer:

5454gjb

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3 0
3 years ago
A student throws a rock upwards. The rock reaches a maximum height 2.4 seconds after it was released.
Allisa [31]

Answer:

23.52 m/s

Explanation:

The following data were obtained from the question:

Time taken (t) to reach the maximum height = 2.4 s

Acceleration due to gravity (g) = 9.8 m/s²

Initial velocity (u) =..?

At the maximum height, the final velocity (v) is zero. Thus, we can obtain how fast the rock (i.e initial velocity)

was thrown as follow:

v = u – gt (since the rock is going against gravity)

0 = u – (9.8 × 2.4)

0 = u – 23.52

Collect like terms

0 + 23.52 = u

u = 23.52 m/s

Therefore, the rock was thrown at a velocity of 23.52 m/s.

7 0
3 years ago
In an old-fashioned amusement park ride, passengers stand inside a 3.0-m-tall, 5.0-m-diameter hollow steel cylinder with their b
lesya692 [45]

Answer:2.55 rad/s

Explanation:

Given

Diameter of ride=5 m

radius(r)=2.5 m

Static friction coefficient range=0.60-1

Here Frictional force will balance weight

And limiting  frictional force is provided by Centripetal force

f=\mu N=\mu m\omega ^2\cdot r

weight of object=mg

Equating two

f=mg

\mu m\omega ^2\cdot r=mg

\omega ^2=\frac{g}{\mu r}

\omega =\sqrt{\frac{g}{\mu r}}

\omega =2.55 rad/sec

8 0
3 years ago
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