Answer:
Explanation:
The question is incomplete.
The equation of motion is given for a particle, where s is in meters and t is in seconds. Find the acceleration after 4.5 seconds.
s= sin2(pi)t
Acceleration = d²S/dt²
dS/dt = 2πcos2πt
d²S/dt² = -4π²sin2πt
A(t) = -4π²sin2πt
Next is to find acceleration after 4.5 seconds
A(4.5) = -4π²sin2π(4.5)
A(4.5) = -4π²sin9π
A(4.5) = -4π²sin1620
A(4.5) = -4π²(0)
A(4.5) = 0m/s²
O2 refers to two oxygen atoms bonded together, while 2 O refers to two oxygen atoms that are not bonded to each other. They both have two oxygen atoms, but in O2, the oxygen atoms are bonded, while in 2O, the atoms are not.
Answer:
false
Explanation:
Understand Newton’s first law of motion. Experience suggests that an object at rest will remain at rest if left alone, and that an object in motion tends to slow down and stop unless some effort is made to keep it moving. An object will go on forever if there were no forces to act upon it. In space, a rocket will go forever at the speed it projects.
Given:
mass is 3.1 kilograms
The acceleration due to gravity
is 9.8m/s2
Required:
Weight
Solution:
W = mg
W = (3.1 kilograms)( 9.8m/s2)
W = 30.38 Newtons
Answer:
(a)
![\lambda _{m}=9.332 \times 10^{-6}m](https://tex.z-dn.net/?f=%5Clambda%20_%7Bm%7D%3D9.332%20%5Ctimes%2010%5E%7B-6%7Dm)
(b)
![\lambda _{m}=1.632 \times 10^{-6}m](https://tex.z-dn.net/?f=%5Clambda%20_%7Bm%7D%3D1.632%20%5Ctimes%2010%5E%7B-6%7Dm)
(c) ![\lambda _{m}=4.988 \times 10^{-7}m](https://tex.z-dn.net/?f=%5Clambda%20_%7Bm%7D%3D4.988%20%5Ctimes%2010%5E%7B-7%7Dm)
Explanation:
According to the Wein's displacement law
![\lambda _{m}\times T = b](https://tex.z-dn.net/?f=%5Clambda%20_%7Bm%7D%5Ctimes%20T%20%3D%20b)
Where, T be the absolute temperature and b is the Wein's displacement constant.
b = 2.898 x 10^-3 m-K
(a) T = 37°C = 37 + 273 = 310 K
![\lambda _{m}=\frac{b}{T}](https://tex.z-dn.net/?f=%5Clambda%20_%7Bm%7D%3D%5Cfrac%7Bb%7D%7BT%7D)
![\lambda _{m}=\frac{2.893\times 10^{-3}}{310}](https://tex.z-dn.net/?f=%5Clambda%20_%7Bm%7D%3D%5Cfrac%7B2.893%5Ctimes%2010%5E%7B-3%7D%7D%7B310%7D)
![\lambda _{m}=9.332 \times 10^{-6}m](https://tex.z-dn.net/?f=%5Clambda%20_%7Bm%7D%3D9.332%20%5Ctimes%2010%5E%7B-6%7Dm)
(b) T = 1500°C = 1500 + 273 = 1773 K
![\lambda _{m}=\frac{b}{T}](https://tex.z-dn.net/?f=%5Clambda%20_%7Bm%7D%3D%5Cfrac%7Bb%7D%7BT%7D)
![\lambda _{m}=\frac{2.893\times 10^{-3}}{1773}](https://tex.z-dn.net/?f=%5Clambda%20_%7Bm%7D%3D%5Cfrac%7B2.893%5Ctimes%2010%5E%7B-3%7D%7D%7B1773%7D)
![\lambda _{m}=1.632 \times 10^{-6}m](https://tex.z-dn.net/?f=%5Clambda%20_%7Bm%7D%3D1.632%20%5Ctimes%2010%5E%7B-6%7Dm)
(c) T = 5800 K
![\lambda _{m}=\frac{b}{T}](https://tex.z-dn.net/?f=%5Clambda%20_%7Bm%7D%3D%5Cfrac%7Bb%7D%7BT%7D)
![\lambda _{m}=\frac{2.893\times 10^{-3}}{5800}](https://tex.z-dn.net/?f=%5Clambda%20_%7Bm%7D%3D%5Cfrac%7B2.893%5Ctimes%2010%5E%7B-3%7D%7D%7B5800%7D)
![\lambda _{m}=4.988 \times 10^{-7}m](https://tex.z-dn.net/?f=%5Clambda%20_%7Bm%7D%3D4.988%20%5Ctimes%2010%5E%7B-7%7Dm)