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3 years ago

8

As a tractor pulls a plow across a field, it exerts a force on the plow in the forward direction. What is the "equal and opposit

e force" in this interaction, according to Newton's third law?

1 answer:

Karolina [17]3 years ago

7 0

Answer:

the force of the plow pulling backward on the tractor

Explanation:

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Thinking about an analogue clock, calculate the angular displacement in revolutions, radians and degrees for the following: • A

Inessa [10]

Answer:

1.047 rad

Explanation:

A secondhand makes a complete revolution (360 degrees) in 60 seconds, so it displaces 6 degrees for every second of elapsed time (360/60 = 6).

And in 10 seconds, it will make a displacement of 10 degrees (6 * 10 = 60).

Finally converting the result into Radians by multiplication with π/180.

5 0

2 years ago

a) A Kuiper Belt Object orbits the Sun with an average orbital distance of 40 AU. What is its orbital period? Round your answer

denpristay [2]

Answer:

253 years

Explanation:

a = Distance in Astronomical units from the sun = 40 AU

P = Orbital period in years

From Kepler's law we have

$P^2=a^3$

$\Rightarrow P^2=40^3$

$\Rightarrow P^2=64000$

$\Rightarrow P=\sqrt{64000}$

$\Rightarrow P=252.982212813$

$\Rightarrow P\approx 253\ years$

The orbital period of the Kuiper belt object is 253 years.

7 0

3 years ago

A small airplane is sitting at rest on the ground. Its center of gravity is 2.58 m behind the nose of the airplane, the front wh

otez555 [7]

Answer:

The percentage of the weight supported by the front wheel is A= 19.82 %

Explanation:

From the question we are told that

The center of gravity of the plane to its nose is $z = 2.58 m$

The distance of the front wheel of the plane to its nose is $l = 0.800\ m$

The distance of the main wheel of the plane to its nose is $e = 3.02 \ m$

At equilibrium the Torque about the nose of the airplane is mathematically represented as

$mg (z- l) - G_B *(e - l) = 0$

Where m is the mass of the airplane

$G_B$ is the weight of the airplane supported by the main wheel

So

$G_B =\frac{mg (z-l)}{(e - l)}$

Substituting values

$G_B =\frac{mg (2.58 -0.8 )}{(3.02 - 0.80)}$

$G_B = 0.8018 mg$

Now the weight supported at the frontal wheel is mathematically evaluated as

$G_F = mg - G_B$

Substituting values

$G_F = mg - 0.8018mg$

$G_F = (1 - 0.8018) mg$

$G_F = 0.1982 mg$

Now the weight of the airplane is = mg

Thus percentage of this weight supported by the front wheel is $A = 0. 1982 *100 =$ 19.82 %

7 0

3 years ago

What is your question?

Papessa [141]

) 5 -5 1 2 3 4 5 Other than at t = 0, when is the velocity of the object equal to zero? 1. 5.0 s 2. 4.0 s 3. 3.5 s 4. At no other time on this graph. correct 5. During the interval from 1.0 s to 3.0 s. Explanation: Since vt = Z t 0 a dt, vt is the area between the acceleration curve and the t axis during the time period from 0 to t. If the area is above the horizontal axis, it is positive; otherwise, it is negative. In order for the velocity to be zero at any given time t, there would have to be equal amounts of positive and negative area between 0 and t. According to the graph, this condition is never satisfied. 005 (part 1 of 1) 0 points Identify all of those graphs that represent motion at constant speed (note the axes carefully). a) t x b) t v c) t a d) t v e) t a

6 0

3 years ago

A plumber is going to put two pipes in a wall, one in front and one in back. The pipes will be touching once they are installed.

beks73 [17]

Answer:

They become the same exact tempature

Explanation:

Since they got connected it should be the same.

8 0

3 years ago