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Zarrin [17]
3 years ago
15

The volume and the mass of substance are 15cm3 and 27 gm respectively find its density​

Physics
1 answer:
harina [27]3 years ago
8 0

Answer:

d=1.8\ g/cm^3

Explanation:

Given that,

Mass, m = 27 grams

Volume of the substance, V = 15 cm³

We need to find the density of the substance. We know that, the density of an object is given by mass per unit volume. So,

d=\dfrac{m}{V}\\\\d=\dfrac{27}{15}\\\\d=1.8\ g/cm^3

So, the density of the substance is equal to 1.8\ g/cm^3.

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1. The resistance of an electric device is 40,000 microhms. Convert that measurement to ohms.
lidiya [134]

Answer:

The answer would be 0.04ohms.

Explanation:

Hopefully this helps

4 0
3 years ago
Read 2 more answers
Which data set has the smallest standard deviation?
hjlf

Answer:

B. 22,22,23,23,22,22,23

Explanation:

The standard deviation is a measure of dispersion or variability of a data set. In order to determine the data set that has the smallest standard deviation, we shall investigate on the ranges of the data sets given. The range of a data set is simply the difference between the maximum and minimum values in a data set. A data set that has a smaller range also has a smaller standard deviation.

From the alternatives given, the data set given by alternative B has the smallest range and consequently the smallest standard deviation.

The maximum value is 23 while the minimum is 22. The range is 1.

5 0
3 years ago
Electromagnetic radiation with a wavelength of 525 nm appears as green light to the human eye. Calculate the frequency of this l
12345 [234]

Answer:

5.71×10¹⁴ Hz

Explanation:

Applying,

v = λf................. Equation 1

Where v = speed of the electromagnetic radiation, λ = wavelength of the electromagnetic radiation, f = frequency

make f the subject of the equation

f = v/λ............. Equation 2

From the question,

Given: λ = 525 nm = 5.25×10⁻⁷ m,

Constant: Speed of electromagnetic wave (v) = 3.0×10⁸ m/s

Substitute these values into equation 2

f = (3.0×10⁸)/(5.25×10⁻⁷)

f = 5.71×10¹⁴ Hz

Hence the frequency of light is 5.71×10¹⁴ Hz

5 0
3 years ago
A skydiver of mass 80.0 kg jumps from a slow-moving aircraft and reaches a terminal speed of 50.0 m/s. (a) What is her accelerat
kirill [66]

Answer:

6.22²

Explanation:

Given that

Mass of the skydiver, m = 80 kg

Terminal speed of the skydiver, v(f) = 50 m/s

Speed of the skydiver, v(i) = 30 m/s

Acceleration of the skydiver, a = ?

To solve this, we use the formula

W - k v² = ma, where

W = weight of the skydiver

k = constant

v = speed of the skydiver

m = mass of the skydiver

So, if we substitute the values into it we have

W = mg = 80 * 9.8 = 784 N

784 - k 50² = 80 *0

784 - 2500k = 0

784 = 2500k

k = 0.3136

Now, we use this value of k to find the needed acceleration using the same formula at a speed of 30 m/s

784 - 0.3136 * 30² = 80 * a

784 - 0.3136 * 900 = 80a

784 - 282.24 = 80a

497.76 = 80a

a = 497.76 / 80

a = 6.22 m/s²

Thus, we can conclude that the acceleration when the speed of the skydiver is 30 m/s, is 6.22 m/s²

4 0
3 years ago
If the magnet is now pushed into the coil and then held stationary inside the coil describe fully what would you observe on the
alexira [117]

Answer:

E = q V B     describes the electric field induced

E Proportional to V B

while the magnet is pushed into the coil the induced field (B) will increase (consider 1 turn of the coil)

If V is constant the E-field will increase due to increasing B and the galvanometer will deflect accordingly

When V drops to zero the deflection must again be zero

So one would see a blip due to the deflection of the galvanometer

Note that as V increases the galvanometer will deflect one way and then as V drops to zero the deflection will be opposite (drop to zero when V is zero)

B always increases to a constant value because of the properties of the magnet.

8 0
2 years ago
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