In order to find the solid, you would want the object in which sound travels the fastest
In this case, since in object C, the speed of sound is the fastest, it is the most likely to be a solid
So object C is most likely to be a solid
Answer:
t = 0.2845Nm (rounded to 4 decimal places)
Explanation:
The disk rotates at a distance of an arc length of 28cm
Arc length = radius × central angle × π/180
28cm = 10cm × central angle × π/180
Central angle = 
× 180/π ≈ 160.4°
Torque (t) = rFsin(central angle) , where F is the applied force
Radius in meters = 10/100 = 0.1m
t = 0.1m × 16N × sin160.4°
t = 0.2845Nm (rounded to 4 decimal places)
Answer:
Lenz’s law states that an induced magnetic field in a conductor opposes the applied flux through the conductor.
Explanation:
According to the Lenz's law, the direction of induced e.m.f is such that it generates a current which in turn produces a magnetic field that would oppose the change causing it.
In other words, the direction of any magnetic induction effect is such that it opposes the cause of the effect.
Therefore; an induced magnetic field in a conductor, opposes the applied flux through the conductor.
Answer:
Explanation:
Given that,
The uncertainty in the position of an electron along the x-axis is, 
We need to find the east uncertainty in any simultaneous measurement of the momentum component of this electron.
We know that the Heisenberg's uncertainty principle gives the relation between the uncertainty in position and the momentum of electron as :
Putting all the values, we get :
So, the momentum component of this electrons is greater than 
.
Answer:
a. an increase in the mass on the spring.
Explanation:
An increase in the mass on the spring will increase the period of an oscillating spring mass system.
Mathematically, the period of an oscillating spring mass system is given by the formula;
T = 2π √(m/k)
Where;
T is the period.
m is the mass of the spring.
k is the spring constant.
Hence, the mass of a spring is directly proportional to the period of oscillation of the spring.
This ultimately implies that, as the mass of the spring increases, the period of oscillation will increase. Similarly, the period of oscillation will decrease with an increase in the spring constant.
