The vertex is the minimum or the maximum point of the parabola.
<em>x and f(x) represent the horizontal and the vertical coordinates of the vertex.</em>
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The standard form of a parabola is
The x coordinate of the parabola is calculated using:
The value of the x-coordinate is then plugged in, into the equation to calculate the y-coordinate, as follows:
At the end of the calculation,
x and f(x) represent the horizontal and the vertical coordinates of the vertex.
Take for instance:
The x-coordinate of the vertex is:
The y-coordinate is:
So, the vertex of is (-1,11)
See attachment for illustration of vertex of
Read more about vertex of parabola at:
brainly.com/question/20209326
Let the smaller integer be x.
The larger integer is x + 1.
x(x + 1) = 420
x^2 + x = 420
x^2 + x - 420 = 0
The constant is -420.
We know that
(ad)/(bd)=d/d time a/b=a/b since d's cancel
also
if a/b=c/d in simplest form, then a=c and b=d
we have
p/(x^2-5x+6)=(x+4)/(x-2)
therefor
p/(x^2-5x+6)=d/d times (x+4)/(x-2)
p/(x^2-5x+6)=d(x+4)/d(x-2)
therefor
p=d(x+4) and
x^2-5x+6=d(x-2)
we can solve last one
factor
(x-6)(x+1)=d(x-2)
divide both sides by (x-2)
[(x-6)(x+1)]/(x-2)=d
sub
p=d(x+4)
p=([(x-6)(x+1)]/(x-2))(x+4)
Here my work! Hope this help!
Answer:
Y= 2x+2
Step-by-step explanation:
line equation is y=mx +c
m is the gradient = 2
We are given an x and y value
X= 1
y= 4
substitute that into the equation:
4= 2(1) +c
2=c
Put all the equation together:
Y= 2x+2
