Question

One number is 6 more than twice the other number. If the sum of the two numbers is ​21, find the two numbers

Answer 1

Answer:

One number, let's call it x, is 6 more than twice the other number, let's say this number is y.

x= 2y+6

x+y=21

We're left with a system of equations.

If we substitute the first equation in the second we find the value of y.

(2y+6)+y=21

3y+6=21

3y=15

y=5

Now that we have found the value of y, we can take that value and substitute it in the second equation (since it's easier) to find the value of x.

x+ (5)=21

x=16

Now to check if our answers are correct, we plug in both values into any equation and see if they equate.

x+y=21

(16)+(5)=21

21=21

Our solution is correct!