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Molodets [167]
2 years ago
6

One number is 6 more than twice the other number. If the sum of the two numbers is ​21, find the two numbers

Mathematics
1 answer:
hichkok12 [17]2 years ago
4 0

Answer:

One number, let's call it x, is 6 more than twice the other number, let's say this number is y.

x= 2y+6

x+y=21

We're left with a system of equations.

If we substitute the first equation in the second we find the value of y.

(2y+6)+y=21

3y+6=21

3y=15

<u><em>y=5</em></u>

Now that we have found the value of y, we can take that value and substitute it in the second equation (since it's easier) to find the value of x.

x+ (5)=21

<u><em>x=16</em></u>

<u><em>Now to check if our answers are correct, we plug in both values into any equation and see if they equate.</em></u>

x+y=21

(16)+(5)=21

21=21

Our solution is correct!

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If the first two statements are true, then the third statement:

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<h3>if the first two statements are true, is the third statement true?</h3>

The first statement is:

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We assume that this is true, so, if X is a dog, X likes walks.

The second statement is:

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From this, we only can conclude that Bandit doesn't like walks.

And all dogs like walks, so if Bandit were a dog, he would like walks, but because he does not like walks, we can conclude that Bandit is not a dog.

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So we write that as a conditional statement:

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If you want to learn more about conditional statements:

brainly.com/question/11073037

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2 years ago
The volume of a cone with a radius of 6 and height of 15
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