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Ivan
2 years ago
5

Empirical formula for C2H4O2

Chemistry
1 answer:
bezimeni [28]2 years ago
6 0

Answer:

Hi

Explanation:

The molecular formula of CH 3 COOH can be written as C2H4O2 . The ratios of C: H:O. are 2:4:2. The highest common factor of 2 and 4 is 2.

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At what temperature is the following reaction at equilibrium? 2Na, O, + 2H,0 + 4NaOH + O, AH° = -109 kJ, ASO = -133.2 J/K
natali 33 [55]

Answer:

Temperature = 818 K

Explanation:

The given reaction is:

2Na2O2 + H2O \rightarrow 4NaOH + O2

The change in enthalpy is: ΔH°= -109 kJ

The change in entropy is : ΔS° = -133.2 J/k = -0.1332 kJ/K

Based on the Gibbs-Helmholtz equation the standard free energy change is given as:

\Delta G^{0}=\Delta H^{0}-T\Delta S^{0}

At equilibrium ΔG° = 0. therefore:

\Delta H^{0} = T\Delta S^{0}

T=\frac{\Delta H^{0}}{\Delta S^{0}}=\frac{-109}{-0.1332}=818 K

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3 years ago
Suppose you have an Internet friend who study chemistry just like you are your friend claims the change from liquid water to wat
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3 years ago
200mL of 4.98M of sodium chloride solution is added to an additional 532 ml of water what is the final molarity?
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Answer:

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Explanation:

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M₂ = 1.9 M

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(Credits to google)
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3 years ago
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