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Ivan
2 years ago
5

Empirical formula for C2H4O2

Chemistry
1 answer:
bezimeni [28]2 years ago
6 0

Answer:

Hi

Explanation:

The molecular formula of CH 3 COOH can be written as C2H4O2 . The ratios of C: H:O. are 2:4:2. The highest common factor of 2 and 4 is 2.

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Explanation:

The given reaction is as follows.

       2SO_{2} + O_{2}(g) \rightarrow 2SO_{3}(g)

Value of equilibrium constant is given as K_{c} = 4.3 \times 10^{6}[/tex].

Concentration of given species is [SO_2] = 0.010 M; [SO_3] = 10.M; [O_2] = 0.010 M.

Formula for experimental value of equilibrium constant (Q) is as follows.

             Q = \frac{[SO_{3}]^{2}}{[SO_{2}]^{2}[O_{2}]}

Putting the given concentration as follows.

              Q = \frac{[SO_{3}]^{2}}{[SO_{2}]^{2}[O_{2}]}

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It is known that when Q > K_{eq}, then reaction moves in the backward direction.

When Q < K_{eq}, then reaction moves in the forward direction.

When Q = K_{eq}, then reaction is at equilibrium.

As, for the given reaction Q > K_{eq} then it means reaction moves in the backward direction.

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For calorimeter

q calorimeter  = C x  ΔT  where C: heat capacity of calorimeter = 69.6 ºC

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q calorimeter = 69.60J x 2.06 ºC = 143.4 J

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Converting into kilojoules by dividing by 1000 we will have answered the question:

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