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3 years ago

Calculate the boiling point of a 2.00 molal solution of magnesium perchlorate, mg(clo4)2, in water.

Chemistry

1 answer:

vova2212 [387]3 years ago

5 0

Answer:

103.06°C.

Explanation:

To solve this problem, we can use the relation:

ΔTb = i.Kb.m,

Where, i is the van 't Hoff factor.

Kb is the molal boiling point elevation constant of water (Kb = 0.51°C/m).

m is the molality of the solution (m = 2.0 m).

We need to define and find the van 't Hoff factor (i):

van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass.

Mg(ClO₄)₂ is dissociated according to the equation:

Mg(ClO₄)₂ → Mg²⁺ + 2ClO₄⁻,

1 mol of Mg(ClO₄)₂ produces 3 mol of ions (1 mol Mg²⁺ and 2 mol ClO₄⁻).

∴ i = 3/1 = 3.

∴ ΔTb = i.Kb.m = (3)(0.51 °C/m)(2.0 m) = 3.06 °C.

∵ ΔTb = the boiling point in presence of solute (Mg(ClO₄)₂) - the boiling point of pure water.

The boiling point of pure water = 100.0°C.

∴ The boiling point in presence of solute (Mg(ClO₄)₂) = ΔTb + the boiling point of pure water = 3.06 °C + 100.0°C = 103.06°C.

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"The total pressure in a mixture of gases is equal to the sum of partial pressures of each gas"

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Answers are in the explanation

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That means after reaction, concentration of HF decrease increasing F⁻ concentration.

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For the statements:

A. The number of moles of HF will increase. FALSE. HF react with KOH, thus, moles of HF decrease

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