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kherson [118]
2 years ago
9

If a+b-c=d, if a-b+c=e, then a= ?

Mathematics
1 answer:
yaroslaw [1]2 years ago
4 0
A + b = d+c 
<span>a - b = e - c </span>
The b and c cancel out. 
<span>2a = d+e </span>
<span>a = (d+e)/2 </span>

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A rug is to be centered in a room so that the border around it is of a consistent width on all four sides. If the room is 10 ft
aleksley [76]

Answer:

The width of the border can be 9 feet or 3.5 feet.

Step-by-step explanation:

Let the width be x

Length of room = 10 feet

Breadth of room = 15 feet

Length of rug = 10-2x

Breadth of rug = 15-2x

Area of rug = (10-2x)(15-2x)  

We are given that the area of the rug is 24 square feet.

So,  (10-2x)(15-2x)=24 ---A

150-20x-30x+4x^2=24

150-24-50x+4x^2=0

126-50x+4x^2=0

2(x-9)(2x-7)=0

x=9,\frac{7}{2}

x=9,3.5

Substitute x =9 in A

(10-2(9))(15-2(9))=24

24=24

LHS = RHS

Substitute x = 3.5

(10-2(3.5))(15-2(3.5))=24

24=24

LHS = RHS

So, The width of the border can be 9 feet or 3.5 feet.

7 0
3 years ago
Suppose sarah is trying to design a metal box (a rectangular prism), which will hold 450 cubic centimeters of liquid. the length
schepotkina [342]
<span>So, the volume of a container can also be thought of as the amount of liquid that the container is capable of holding. It follows that 450=(length)(width)(height). The constraints of the problem say that the length of the box must be twice as large as the width, so it follows that j(height)=(2w)(w)(height)-450. This then implies that j(height)=(2w^2)(height)-450. In simpler terms, the height is defined as 450/(2w^2), or j(w)=450/(2w^2).</span>
5 0
3 years ago
Distance between parallel lines y=3x+10 and y=3x-20
Alecsey [184]

1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).


2. Use formula d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}} to find the distance from point (x_0,y_0) to the line Ax+By+C=0.


The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:

d=\dfrac{|3\cdot 0-10-20|}{\sqrt{3^2+(-1)^2}}=\dfrac{30}{\sqrt{10}}=3\sqrt{10}.


3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.


Answer: d=3\sqrt{10}.

4 0
2 years ago
2+5+2) = 6(+2)
Sergio039 [100]

cuatro no? porque osea tiene q

5 0
3 years ago
What is -3/4 x 7/8 <br> whats negative three over four times seven over eight.
UNO [17]

Answer:

-21/32

Step-by-step explanation:

It's easier to do this multiplication mentally if we rewrite the expression as follows:

 -3        7       -21

------ * ------ = ---------

  4         8       32

5 0
2 years ago
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