Question

Find an equation of a line with slope -3/4 and that passes through P(-4,6) in standard, form.

Answer 1

Answer:

$y = - \frac{3}{4}x + 3$

Step-by-step explanation:

the standard form of any straight line is:

y = m × x + c

where: y is the y value of the point

x is the x value of the point

m is the gradient/slope

SOLUTION

$y = mx + c \\ 6 = - \frac{3}{4} ( - 4) + c \\ c = 3$