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Igoryamba
2 years ago
8

Find an equation of a line with slope -3/4 and that passes through P(-4,6) in standard, form.

Mathematics
1 answer:
SashulF [63]2 years ago
3 0

Answer:

y = -   \frac{3}{4}x  + 3

Step-by-step explanation:

the standard form of any straight line is:

y = m × x + c

where: y is the y value of the point

x is the x value of the point

m is the gradient/slope

SOLUTION

y = mx + c \\ 6 =  -  \frac{3}{4} ( - 4) + c \\ c = 3

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svlad2 [7]

Answer:

1.025%

Step-by-step explanation:

1.025 / 100 = 1.025%

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8 0
3 years ago
10 + 7x = -8 ( x -7)
tresset_1 [31]

10+7x = -8x+56

15x=46

x=46/15

4 0
3 years ago
What is the value of y to find the angles
Lorico [155]
A triangles degrees add up to 180.
well first 180-138 for angle u which is 42

then do 42+(6y-2)+(8y+14)=180

solve for y.

42+(6y-2)+(8y+14)=180

42+6y-2+8y+14=180
54+14y=180
-54            -54
14y=126
/14      /14
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8 0
3 years ago
4. Write an explicit formula for the sequence 6,2, -2, -6, -10.... Then find the 12th term
blsea [12.9K]

Answer:

-38

Step-by-step explanation:

general formula

a + (n-1)(d)

formula for this question

6 + (n-1)(-4)

find d

2-6=-2-2

-4=-4

d=-4

a=6 d=-4

12th term

T12= 6+(12-1)(-4)

= 6 + (-44)

=-38

hope this helps :)

4 0
2 years ago
Identify the y-intercept in the equation y = -3x - 1
Viktor [21]
Y=mx+b
Remember the m value is always your slope so in this case your slope would be -3
6 0
3 years ago
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