Answer:
The cost of driving this car is 33.33 miles per dollar.
Explanation:
Distance covered in 1 kilo watt-hour = 4 miles/kWh
Utility company charges = 12 cents/kWh
The cost of driving this car in miles per cents:
1 cents = 0.01$
The cost of driving this car in miles per dollars:
Single displacement is the type of chemical reaction
Answer:
KHP + NaOH ⟶ KNaP + H₂O
Explanation:
The H in KHP is the acidic hydrogen. The OH⁻ in NaOH neutralizes it and converts it to H₂O.
The balanced equation for the reaction is
KHP + NaOH ⟶ KNaP + H₂O
Ecell = E°cell - RT/vF * lnQ
R is the gas constant: 8.3145 J/Kmol
T is the temperature in kelvin: 273.15K = 0°C, 25°C = 298.15K
v is the amount of electrons, which in your example seems to be six (I'm not totally sure)
F is the Faradays constant: 96485 J/Vmol (not sure about the mol)
Q is the concentration of products divided by the concentration of reactants, in which we ignore pure solids and liquids: [Mg2+]³ / [Fe3+]²
Standard conditions is 1 mol, at 298.15K and 1 atm
To find E°cell, you have to look up the reduction potensials of Fe3+ and Mg2+, and solve like this:
E°cell = cathode - anode
Cathode is where the reduction happens, so that would be the element that recieves electrons. Anode is where the oxidation happens, so that would be the element that donates electrons. In your example Fe3+ recieves electrons, and should be considered as cathode in the equation above.
When you have found E°cell, you can just solve with the numbers I gave you.
Studies reveal that during colder glacial periods, carbon dioxide levels were lower than during warmer interglacial periods. Glacial periods are intervals of time within an ice age that is marked by colder temperatures and glacier advances. Interglacials, on the other hand, are periods of warmer climate between glacial periods.
