Answer:
Lake
Explanation:
Yeah...not much else to say honestly
Answer:
1. Hydrogen ions; acidic
2. Alkali; hydroxide ions; alkaline
3a. Sulfuric acid --> 2 Hydrogen ions + sulfate ion
H₂SO₄ --> 2H+ + SO₄²-
3b. Sodium hydroxide --> Sodium ion + Hydroxide ion
NaOH --> Na+ + OH-
Explanation:
1. Sulfuric acid releases hydrogen ions in solution. This makes the solution acidic.
Acids produce hydrogen ions when dissolved in aqueous solutions.
2. Sodium hydroxide is an alkali. It releases hydroxide ions in solution. This makes the solution alkaline.
Alkalis are soluble bases that produce hydroxide ions in solution.
3a. Sulfuric acid --> 2 Hydrogen ions + sulfate ions
H₂SO₄ --> 2H+ + SO₄²-
The equation above is for the ionization of sulfuric acid
b. Sodium hydroxide --> Sodium ion + Hydroxide ion
NaOH --> Na+ + OH-
The equation above is for the ionization of sodium hydroxide
Answer:
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Explanation:
Answer:
See figure 1
Explanation:
In this question, we have to find first the <u>chiral carbons</u> on 1,2-difluoro-1,2-dimethylcyclopentane. Carbons 1 and 2. Then, using the <u>Cahn–Ingold–Prelog priority rules</u>. We can draw all the stereoisomers. If we have 2 chiral carbons we will have (
) <u>4 isomers</u>. With this in mind we can have the R,R isomer; the S,S isomer; the S,R isomer, and the R,S isomer. We have to remember that:
<u>Priority 1 = "F"</u>
<u>Priority 2= "C"</u>
<u>Priority 3= "CH2"</u>
<u>Priority 4 = "CH3"</u>
I hope it helps!
Answer:
Explanation:
From the equation:
H2SO4(aq) + 2NaOH(aq) --> Na2SO4(aq) + 2H2O (l)
<em>1 mole of the acid (H2SO4) and 2 moles of the base (NaOH) are required for complete neutralization.</em>
mole of acid (H2SO4) present = molarity x volume
= 1 x 0.1 = 0.1 mole
Mole of base (NaOH) present = mass/molar mass
= 7/40 = 0.175 mole
<em>The ratio of acid and base should be 1:2, hence the acid is slightly excessive in this case and the base is the limiting reagent that will determine the extent of the reaction.</em>
Amount of excess acid = 0.1 - 0.175/2
= 0.0125 mole
volume of excess acid = mole/molarity
= 0.0125 x 1 = 0.0125 L
= 12.5 mL
<em>Hence, the acid (H2SO4) was in excess by 12.5 mL.</em>