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AnnyKZ [126]
3 years ago
10

What type of chemical reaction occurs between silver nitrate (AgNO3) and Copper (Cu)? The equation I was given is 2AgNO3 + Cu —&

gt; 2Ag+ Cu(NO3)2.
Chemistry
1 answer:
Pie3 years ago
5 0
Single displacement is the type of chemical reaction
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If all other variables remain unchanged, what happens to the output force when the area of the input piston is doubled?
mars1129 [50]

Answer:

1250N

Explanation:

This question is based on pascal's Law.

So By Pascal's Law

 =  

therefore  =force on input piston =25N

                  = Force or weight on output person.

therefore after putting the values we get,

= (25x 1500)/30

    =1250N

3 0
3 years ago
In a reaction, chlorine accepts an electron to form Cl-. What is true about the atomic size of the chlorine ion?
Lynna [10]

Answer is: The atomic size of the chlorine ion is larger than the size of the chlorine atom.

Covalent radii of chlorine atom (Cl) is 0.099 nm and ionic radii of chlorine anion (Cl⁻) is 0.181 nm.

Difference between an chlorine atom and chlorine anion is the number of electrons that surround the nucleus.

Chlorine atom has 17 electrons and chlorine anion has 18 electrons.

6 0
3 years ago
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If solid iron is dropped in liquid iron, it will most likely?
S_A_V [24]

it will sink

Explanation:

the solid iron will sink because it is dense than the liquid iron I will sink and it will melt

4 0
3 years ago
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WILL MARK BRAINLIEST!!!!!!!!!!!!!!!!
Westkost [7]

Hello!

I believe the answer is A) Anaphase.

I hope it helps!

3 0
3 years ago
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Consider the reaction below. Initially the concentration of SO2Cl2 is 0.1000 M. Solve for the equilibrium concentration of SO2Cl
tensa zangetsu [6.8K]

Answer:

[SO_2Cl_2] = 0.09983 M

Explanation:

Write the balance chemical equation ,

SO_2Cl_2((g) = SO_2(g) + Cl_2(g)

initial concenration of SO_2Cl_2((g)  =0.1M

lets assume that degree of dissociation=\alpha

concenration of each component at equilibrium:

[SO_2Cl_2] = 0.1-0.1\alpha

[SO_2] = 0.1\alpha

[Cl_2] = 0.1\alpha

Kc =\frac{0.1\alpha \times 0.1\alpha}{0.1-0.1\alpha}

Kc =\frac{0.1\alpha \times \alpha}{1-\alpha}

as \alpha is very small then we can neglect  1-\alpha

therefore ,

Kc ={0.1\alpha \times \alpha}

\alpha =\sqrt{\frac{Kc}{0.1}}

\alpha = 1.73 \times 10^{-3}

Eqilibrium concenration of [SO_2Cl_2] = 0.1-0.1\alpha = 0.1-0.1\times 0.00173

[SO_2Cl_2] = 0.09983 M

4 0
3 years ago
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