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vodka [1.7K]
3 years ago
7

in dimesional analysis, if an electric vehicle gets 4 miles/ kWh and the utility company charges 12 cents per kWh for charging i

ts battery, calculate the cost of driving this car in miles per dollar. (this is for chemistry not math)
Chemistry
1 answer:
Ivanshal [37]3 years ago
3 0

Answer:

The cost of driving this car is 33.33 miles per dollar.

Explanation:

Distance covered in 1 kilo watt-hour = 4 miles/kWh

Utility company charges  = 12 cents/kWh

The cost of driving this car in miles per cents:

\frac{ 4 miles/kWh}{12 cents/kWh}=\frac{1 miles}{3 cents}

1 cents = 0.01$

The cost of driving this car in miles per dollars:

\frac{1}{3} miles/cent=\frac{1 miles}{3\times 0.01\$}=33.33 miles/\$

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In a balanced, non-charged atom, the number of protons (positive charge) is equal to the number of electrons (negative charge)

So there are 92 electrons
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Note the signs of equilibrium:-

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3 years ago
Describe relationships between molecules atoms and a grain of sugar
Contact [7]

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3 years ago
What is the poH of a<br> 2.6 x 10-6 M H+ solution?
andriy [413]

Answer:

Explanation:

pH and pOH.....

The pH is a way of expressing the hydrogen ion concentration.

pH = -log[H+] ............. where [x] means "the concentration of x in moles per liter."

From pH you can compute pOH since at 25C pH + pOH = 14.00 .......... (but only at 25C)

pH = -log(2.6x10^-6) = 5.585 ..... which should be rounded to two significant digits: pH = 5.59

When taking the log of a number, only the digits to the right of the decimal reflect the precision in the original number. Since 2.6x10^-6 has two significant digits, a pH of 5.59 has two significant digits.

pOH + pH = 14.00

pOH = 14.00 - pH = 14.00 - 5.59 = 8.41 ......... at 25C

We can also use the H+ ion concentration to get the hydroxide ion concentration and from that the pOH.

Kw = [H+][OH-] = 1.00x10^-14 .......... at 25C .... like any Kc, the value changes with temperature

[OH-] = Kw / [H+] = 1.00x10^-14 / 2.6x10^-6 = 3.846x10^-9 .... to a couple of guard digits

pOH = -log[OH-] = -log(3.846x10^-9) = 8.415 ...... round to two significant digits: pOH = 8.42 ..... at 25C

=========

Just for grins, you might want to know how Kw changes with temperature, and how [H+] and [OH-] are related at some other temperatures. The pH is the pH of a neutral solution at various temperatures. For instance at 10C a neutral solution has a pH of 7.27. That's not a basic pH. 7.27 is the pH of a neutral solution, but at a different temperature. In a neutral solution at 10C [H+] = [OH-] = 5.41x10^-8M.

pH and Kw for a neutral solution at different temperatures

T .........pH ......... Kw

0......... 7.47....... 0.114 x 10-14

10....... 7.27....... 0.293 x 10-14

20....... 7.08....... 0.681 x 10-14

25....... 7.00....... 1.008 x 10-14

30....... 6.92....... 1.471 x 10-14

40....... 6.77....... 2.916 x 10-14

50....... 6.63....... 5.476 x 10-14

100..... 6.14....... 51.3 x 10-14

4 0
3 years ago
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