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Kobotan [32]
2 years ago
13

Hi, need help please to get my HS diploma...did not graduate :(

Mathematics
1 answer:
Sergio039 [100]2 years ago
7 0

Answer:

B

Step-by-step explanation:

I assume this should look like

V(x) = -x² + 2x - 4

W(x) = -x³ + 2x² + x + 5

when doing arithmetic operations with whole functions, we simply do these operations with the whole expressions :

V(x) × W(x) =

(-x² + 2x - 4) × (-x³ + 2x² + x + 5) =

= x⁵ - 2x⁴ - x³ - 5x² - 2x⁴ + 4x³ + 2x² + 10x + 4x³ - 8x² - 4x - 20 =

= x⁵ - 4x⁴ + 7x³ - 11x² + 6x - 20

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2 years ago
Helpp!!!<br> prove that:<br> cosecA-cotA= tanA/2
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Answer:

tanA/2.

Step-by-step explanation:

some trigonometric properties:

* tanA = sinA/cosA

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2 years ago
The student body President of a high school claims to know the names of at least 1000 of the 1800 students at the school. To tes
hoa [83]

Answer:

The 99% confidence interval for p in this case is (0.3317, 0.5883).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Randomly selects 100 students from the school and asks the President to name each one. The President is able to correctly name 46 of the students.

This means that:

n = 100, \pi = \frac{46}{100} = 0.46

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.46 - 2.575\sqrt{\frac{0.46*0.54}{100}} = 0.3317

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.46 + 2.575\sqrt{\frac{0.46*0.54}{100}} = 0.5883

The 99% confidence interval for p in this case is (0.3317, 0.5883).

4 0
3 years ago
(repost) Help Please I will Give brainliest If Correct!!
Eddi Din [679]

Answer:

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2 years ago
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Calculate the area and perimeter plz help
kramer

Answer:

Figure 1:

Area: 30m^2

Perimeter: 23.6m

Figure 2:

Area: 98.8km^2

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Step-by-step explanation:

Area is base x height.

To get the perimeter, add up all the sides.

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