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tino4ka555 [31]
3 years ago
9

Find the greatest integer value of $b$ for which the expression $\frac{9x^3+4x^2+11x+7}{x^2+bx+8}$ has a domain of all real numb

ers.
Mathematics
1 answer:
vovangra [49]3 years ago
3 0

Consider fraction \dfrac{9x^3+4x^2+11x+7}{x^2+bx+8}. The domain of this fraction is x^2+bx+8\neq 0.

Find the discriminant of the the equation x^2+bx+8=0:

D=b^2-4\cdot 1\cdot 8=b^2-32.

There are choices:

1. If D>0, there are two solutions of the equation;

2. D=0, there is only unique solution of the equation;

3. D<0, there are no solutions.

If x^2+bx+8\neq 0 you should consider case 3, then
b^2-32.

Therefore, the greatest integer is 5.

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Which Pairs are additive inverses?<br> a. 6,-(-6)<br> b. -7,7<br> c.-7,-7<br> d.7,7<br> e.6,-6
xz_007 [3.2K]

I was never sure of what the "additive inverse" is. 
So, just now, just for you, I went and looked it up.

The additive inverse of any number ' A ' is the number
that you need to ADD to A to get zero.  That's all !

So now, let's check out the choices:

a), 6, -(-6)

That second number, -(-6), is the same as +6 .
So the two numbers are the same.
Do you get zero when you add them up ?  No.

b). -7, 7
What do you get when you add -7 and 7 ?
You get zero.
So these ARE additive inverses.

c). -7, -7
What do you get when you add -7 to -7 ?
You get -14 .  That's not zero, so these
are NOT additive inverses.

d).  7, 7
What do you get when you add 7 to 7 ?
You get 14.  That's NOT zero, so these
are NOT additive inverses.

e).  6, -6
What do you get when you add 6 to -6 ?
You get zero.
So these ARE additive inverses.

What do we end up with from the list of choices:

a).,  c).,  and d). are NOT additive inverses.

b). and e). ARE additive inverses.

7 0
3 years ago
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Answer:

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Step-by-step explanation:

4 0
2 years ago
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Dahasolnce [82]

Answer:

234 times

Step-by-step explanation:

<u>Number of times the number 7 appears in a hundred</u>

7 as units digit (07-17-27 ..... 97): 10 times

7 as tens digit (70-71-72..... 79): 10 times

20 times the digit 7 appears in first one hundred (0-100)

Let's calculate how many times 7 would be as units or tens in 7 hundreds

20X7 = 140 times digit 7 appears until number 699

<u>Now, from 700 to 777</u>

7 as hundreds digit (700-701-702 .... 777): 78 times

7 as tens digit (770-771-772 .... 777): 8 times

7 as units digit (707-717-727....777): 8 times

78 + 8 + 8 = 94 times the digit 7 appears in the range 700 - 777. Plus 140 times

140 + 94 = 234 times

4 0
3 years ago
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Need Help Please! <br> attachment below
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Answer:

9 blue marbles

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