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Lady_Fox [76]
2 years ago
12

Throw two balls from the same height at the same time at an initial speed of 20 m/s. One is thrown vertically down, while the ot

her is thrown vertically up. We want to find the time difference between their landing.
Physics
1 answer:
labwork [276]2 years ago
6 0

The time difference between their landing is 2.04 seconds.

<h3>Time of difference of the two balls</h3>

The ball thrown vertical upwards will take double of the time taken by the ball thrown vertically downwards.

Time difference, = 2t - t = t

t = √(2h/g)

where;

  • h is the height of fall
  • g is acceleration due to gravity

Apply the principle of conservation of energy;

¹/₂mv² = mgh

h = v²/2g

where;

  • v is speed of the ball

h = (20²)/(2 x 9.8)

h = 20.41 m

<h3>Time of motion</h3>

t = √(2 x 20.41 / 9.8)

t = 2.04 s

Thus, the time difference between their landing is 2.04 seconds.

Learn more about time of motion here: brainly.com/question/2364404

#SPJ1

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Answer:

Time, t = 0.87 seconds

Explanation:

Given that,

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Using first equation of motion to find it as :

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t=\dfrac{u}{\mu g}\\\\t=\dfrac{4.3}{0.5\times 9.8}\\\\t=0.87\ s

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