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My name is Ann [436]
3 years ago
6

If you walk 30 meters forwards, and then turn around and walk 25 meters backwards, what is the distance that you walked? What di

splacement do you have after this walk?
Physics
1 answer:
xeze [42]3 years ago
5 0

Given :

Walk in forward direction is 30 m .

Walk in backward direction is 25 m .

To Find :

The distance and displacement .

Solution :

We know , distance is total distance covered and displacement is distance between final and initial position .

So , distance travelled is :

D = 30 + 25 m = 55 m .

Now , we first move 30 m in forward direction and then 25 m in backward direction .

So , displacement is :

D = 30 - 25 m = 5 m .

Therefore , distance and displacement covered is 55 m and 5 m respectively .

Hence , this is the required solution .

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Which law is associated with inertia
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Answer:

The focus of Lesson 1 is Newton's first law of motion - sometimes referred to as the law of inertia. An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

4 0
3 years ago
You can comfortably hold your fingers close beside a candle flame, but not very close above the flame. why? challenge (optional)
Inessa05 [86]
The candle flame releases hot gases, which directly go in upwards directions. Due to which the air near the flame of the candle is very hot and dense. The particles along with vapour move up. And since the sideways, the air is not very dense and hot, we are able to hold the candle. In anti-gravity region, there will be no density differences and also, the convection process wont occur. So, the candle quickly snuffs off.
6 0
3 years ago
Read 2 more answers
A gold sphere of radius R=100 μm and density 19g/cm^3 falls through water. Given the viscosity of water is about 10^-3​ Pa s and
icang [17]

The terminal velocity of gold sphere is 39.2 cm/s

<h3>What is terminal velocity?</h3>

Terminal velocity is the maximum velocity attainable for an object as it falls through a fluid.

<h3>How to calculate the terminal velocity of the gold sphere?</h3>

The terminal velocity of the gold sphere is given by v = 2gr²(ρ - σ)/9η where

  • g = acceleration due to gravity = 9.8 m/s²,
  • r = radius of sphere = 100 μm = 100 × 10⁻⁶ m = 10⁻⁴ m = 10⁻² cm,
  • ρ = density of sphere = 19 g/cm³,
  • σ = density of water = 1.0 g/cm³ and
  • η = viscosity of water = 10⁻³ Pa-s

So, susbtituting the values of the variables into the equation, we have that

v = 2gr²(ρ - σ)/9η

v = 2 × 9.8m/s²× (10⁻² cm)²(19 g/cm³ - 1.0 g/cm³)/(9 × 10⁻³ Pa-s)

v = 2 × 9.8 m/s² × 10⁻⁴ cm² × (18 g/cm³)/(9 × 10⁻³ Pa-s)

v = 2 × 980 cm/s² × 10⁻⁴ cm² × 2 g/cm³/(1 × 10⁻³ Pa-s)

v = 3920 g/s² × 10⁻⁴/(1 × 10⁻³ Pa-s)

v = 392 cm/s × 10³ × 10⁻⁴

v = 392 × 10⁻¹ cm/s

v = 39.2 cm/s

So, the terminal velocity is 39.2 cm/s

Learn more about terminal velocity of sphere here:

brainly.com/question/21684177

#SPJ1

4 0
1 year ago
A cat is moving at 18 m/s when it accelerates for 2 seconds. What is its acceleration?
vova2212 [387]

Answer: acceleration:4 m/s^{2}

              velocity: 26 m/s

Explanation:

The complete question is written bellow:

<em>A cat is moving at 18 m/s when it accelerates at </em>4 m/s^{2}<em> for 2 seconds. What is his new velocity?  </em>

<em />

In this situation the following equation will be useful:

V=V_{o}+at

Where:

V is the cat’s final velocity (new velocity)

V_{o}=18 m/s is the cat’s initial velocity

a=4 m/s^{2} is the cat's acceleration

t=2 s is the time

Solving the equation:

V=18 m/s+(4 m/s^{2})(2 s)

V=26 m/s This is the cat's new velocity

5 0
3 years ago
Solar energy leaves the core of the sun in the form of
olasank [31]

photons and convection - density differences makes bubbles of hot stuff float up.   pretty sure

3 0
3 years ago
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