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svetlana [45]
3 years ago
5

John’s mass is 95.6 kg, and Barbara’s is 55.3 kg. He is standing on the x axis at xJ = +10.9 m, while she is standing on the x a

xis at xB = +2.50 m. They switch positions. How far and in which direction does their center of mass move as a result of the switch? Distance moved by center of mass =
Physics
1 answer:
Anna11 [10]3 years ago
8 0

Answer:Shifted towards Left by distance of 2.243 m

Explanation:

Given

Mass of john m_1=95.6 kg

Mass of barbara m_2=55.3 kg

John is standing at x=10.9 m

Barbara is standing at x=2.50 m

x_{com}=\frac{m_1x_1+m_2x_2}{m_1+m_2}

x_{com}=\frac{95.6\times 10.9+55.3\times 2.5}{95.6+55.3}

x_{com}=\frac{1180.29}{150.9}

x_{com}=7.821 m

Now if they change their Position then

x'_{com}=\frac{95.6\times 2.5+55.3\times 10.9}{95.6+55.3}

x'_{com}=\frac{841.77}{150.9}

x'_{com}=5.578

Thus we can see that center of mass shifted towards left by a distance of 2.243 m because heavier is shifted towards left

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a) y(max)  = 337.76 m

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y  =  y₀ + v₀y*t - (1/2)*g*t²      (1)

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0 = 200 + 30*√3*t₂  - 4.9*t₂²            4.9 t₂² - 51.96*t₂ - 200 = 0

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t₂ =  13.60 s  time for y = 0 time when the fly finish

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x = vₓ * t

x = 30 * 13.60  m

x = 408 m

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