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Leona [35]
4 years ago
15

Which two of the following are the least dense materials shown?

Physics
2 answers:
sergiy2304 [10]4 years ago
7 0
I did this test, i think its loaf of bread and pillow

uysha [10]4 years ago
3 0
Pillow. When you make the mass of off substances equivalent, the pillow takes up the most volume. This means it is the least dense. 
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Use differentials to estimate the amount of metal in a closed cylindrical can that is 10 cm high and 10 cm in diameter if the me
lana66690 [7]

Answer:

dV = 32.98 cm³

Explanation:

We know that

V = f ( h,r)

dV= \frac{\partial V}{\partial r}dr+ \frac{\partial V}{\partial h}dh

We also know that

V=\pi r^2h

dV= 2\pi h dr + \pi r^2 dh

Given that

h= 10 cm

d=10 cm ,  r= 5 cm

Thickness = 0.05 cm so  dr = 0.05 cm

The metal in the top and the bottom is 0.2 cm thick  so dh = 0.2 + 0.2 cm

dh = 0.4 cm

Now by putting the values

dV= 2\pi h dr + \pi r^2 dh

dV= 2\times \pi \times 5\times 0.05 + \pi \times 5^2\times 0.4\ cm^3

dV = 32.98 cm³

8 0
3 years ago
Help immediately please
icang [17]

Answer:

Speed is a measure of how quickly an object moves from one place to another. It is equal to the distance traveled divided by the time.

3 0
3 years ago
If a ball is tossed straight up into the air, at what position is its potential energy the greatest? Question 3 options: When it
Gennadij [26K]

The ball has the greatest potential energy when it reaches the top of its flight. Option C is correct.

<h3>What is potential energy?</h3>

The potential energy of a body or object is due to its position. The ball has the greatest potential energy when it reaches the highest point.

U = mgh

Where,

U - potential energy

m - mass

g - gravitation acceleration

h - height

Since the mass and gravitation acceleration is constant hence potential energy will be directly proportional to the height of the ball.

Therefore, the ball has the greatest potential energy when it reaches the top of its flight.

Learn more about potential energy:

brainly.com/question/1250558

7 0
3 years ago
ANSWER THE 3 QUESTION WILL MARK AS BRAINLIEST THIS IS 20 POINTS :)))
PtichkaEL [24]
15) a 
16) b
17) a

Hope this helps
3 0
4 years ago
Read 2 more answers
White light (400–700 nm) is incident on a 600 line/mm diffraction grating. What is the width of the first-order rainbow on a scr
Tema [17]

Answer:

Δy=0.431m

Explanation:

Diffraction grating with split space d,to find the fringe position ym,we must to find the angle from

dSinα=mλ

A grating with N slits or lines per mm has slit spacing of

d=1/N

d=(1/600mm)

d=1.67×10⁻³mm

For 400nm wavelength:

α=Sin⁻¹(mλ/d)

\alpha =Sin^{-1}(\frac{400*10^{-9} }{1.67*10^{-6}} )\\ \alpha =13.910^{o}

And the position of first order lowest wavelength fringe on the screen is:

y_{1}=Ltan\alpha_{1}\\y_{1}=2tan(13.910)\\  y_{1}=0.49445m

For 700nm wavelength:

α=Sin⁻¹(mλ/d)

\alpha =Sin^{-1}(\frac{700*10^{-9} }{1.67*10^{-6}} )\\ \alpha_{2}  =24.83^{o}

And the position of first order highest wavelength fringe on the screen is:

y_{2}=Ltan\alpha_{2}\\y_{2}=2tan(24.83)\\  y_{2}=0.925595m

The difference between the first order lowest and highest wavelength fringe is

Δy=(0.925595 - 0.49445)m

Δy=0.431m

6 0
3 years ago
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