For instance, in an alkaline battery, the anode is typically made of zinc, and manganese dioxide acts as the cathode. And the electrolyte between and inside those electrodes contains ions. ... These free electrons congregate inside the anode (the bottom, flat part of an alkaline battery)
Hope this helps:)
Answer:
Animal 1 because it takes 3s to go 25 meters 3.5s to go 50 meters and 5s to go 75 meters while the others take longer.
Explanation:
You can do this all in one Step
Formula
F2/F1 = 8.5/(25r^2) // 1 / r^2
Solution
The "ks, r^2 and q1 q2" all cancel out
You are left with 8.5/25 as the ratio
- F1 = 5.7 N
- F2 = 8.5 / 25 * F1
- F2 = 8.5 / 25 * 5.7
- F2 = 1.938
Answer:
3.9 × 10^7 J
Explanation:
Given that a tank is is half full of oil that has a density of 900 kg/m3. Find the work W required to pump the oil out of the spout. (Use 9.8 m/s2 for g. Assume r = 15 m and h = 5 m.) W = 1.59 J
Solution
Since the tank is half full, the height = 2.5m
Pressure = density × gravity × height
Pressure = 900 × 9.8 × 2.5
Pressure = 22050 Pascal
The cross sectional area of the pump will be area of a circle.
A = πr^2
A = π × 15^2
A = 706.858 m^2
Using the formula
Density = mass/volume
Mass = density × volume
Mass = 900 × 706.86 × 2.5
Mass = 1590.435
Energy = mgh
Energy = 1590.435 × 9.8 × 2.5
Energy = 38965657.8 J
Since the work done = energy
Therefore, the work done = 3.9 × 10^7 J
Answer:
37.18 N
Explanation:
Given:
Work (W) = 483.3 J
Distance (d) = 13 m
We can determine the value of the force as follows:
W = F.d
We replacing:
483.3 = F. 13
F = 483.3 ÷ 13
F = 37.18 N
The force on the block is 37.18 N
