Answer:
• 36.4 kg of coal.
• 80 pounds of coal.
Explanation:
Using proportionality constant,
Mass of coal = 1,000,000/27,500,000 btus/metric ton
= 0.0364 metric tons of coal
Mass of coal = 1,000,000/25,000,000 btus/ton
= 0.04 tons of coal.
Converting metric tons to kilogram,
1 metric ton = 1000kg,
0.0364 metric ton;
= 36.4 kg of coal.
Converting tons to pounds,
1 ton = 2000 pounds,
0.04 metric ton;
= 80 pounds of coal.
Answer:
I think A
Explanation:
because I don't think a unknowned number can be a division problem
Answer:
from the above analysis we can say that the angular velocity in the later case is more than that of the former case. This means that the number of rotation made in the truck case is more than that made in pike position.
Explanation:
This can be explained on the basis of conservation of angular momentum.
This means the initial and the final angular velocity is conserved. Consider initial position (1)in the pike and final position in the be truck position. So there inertia's will also be different.
⇒![I_1\omega_1 = I_2\omega_2](https://tex.z-dn.net/?f=I_1%5Comega_1%20%3D%20I_2%5Comega_2)
![\frac{I_1}{I_2} = \frac{\omega_2}{\omega_1}](https://tex.z-dn.net/?f=%5Cfrac%7BI_1%7D%7BI_2%7D%20%3D%20%5Cfrac%7B%5Comega_2%7D%7B%5Comega_1%7D)
also,
![I_1= mr_1^2](https://tex.z-dn.net/?f=I_1%3D%20mr_1%5E2)
![I_2= mr_2^2](https://tex.z-dn.net/?f=I_2%3D%20mr_2%5E2)
since, ![r_2^2](https://tex.z-dn.net/?f=r_2%5E2%3Cr_1%5E2)
![I_2^2](https://tex.z-dn.net/?f=I_2%5E2%3CI_1%5E2)
therefore,
![\omega_1^2](https://tex.z-dn.net/?f=%5Comega_1%5E2%3C%5Comega_2%5E2)
So, from the above analysis we can say that the angular velocity in the later case is more than that of the former case. This means that the number of rotation made in the truck case is more than that made in pike position.
Answer:
B phase change
Explanation:
because shallow slope always indicades phase change
Answer:
(B) is a volume in space.
Explanation:
A system is the space chosen form the universe for the study and analysis.
There are 3 kinds of systems :
1) Open system:
This system can interact to surroundings in terms of both mass and energy transfer through its boundaries.
2) Closed system:
This type of system can only interact to the surrounding in terms of energy transfer through its boundary.
3) Isolated system:
This type of system cannot interact with the surrounding by any means and its energy remains constant with time under the observation.
It has insulated boundary.