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Maurinko [17]
3 years ago
7

How does the saturation of a solution affect crystal formation? In your own words please

Physics
1 answer:
ryzh [129]3 years ago
3 0

The term saturated solution is used in chemistry to define a solution in which no more solute can be dissolved in the solvent. It is understood that saturation of the solution has been achieved when any additional substance that is added results in a solid precipitate or is let off as a gas.

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Laser transmissions travel at a higher speed than the radio waves true or false
uranmaximum [27]
<span>False. Laser transmissions and radio waves are both forms of electromagnetic radiation. Both travel at approximately 3.00 x 10^8 meters per second. This is the case because wavelength and frequency are directly proportional to this value. Although laser light has a shorter wavelength than radio waves, it will travel at the same speed because the frequency will be greater.</span>
6 0
3 years ago
Technician A says that the diameter of a bolt is the same as the wrench size used to remove or install the fastener. Technician
Iteru [2.4K]

Answer:

Neither Technician A or B

Explanation:

Both technicians are wrong. The diameter of bolt is not based on the top where wrench used, but on the smaller part below, it called shanks. Wrench size also not based on the top diameter but the width across the flat. The calculation for the length of a bolt also will not include the top/head, it only includes the shanks.  

7 0
3 years ago
Solved, can someone check it over! ​
kakasveta [241]

Answer:

its good no need to change anything :))

4 0
3 years ago
Suppose the force of gravity on the electron was comparable to the electric force created by the deflection plates. how would th
Alexandra [31]
"F=Vector Sum Of The Two Forces" Is the answer.
3 0
3 years ago
Two neutron stars are separated by a distance of 1.0 x 1012 m. They each have a mass of 1.0 x 1028 kg and a radius of 1.0 x 103
son4ous [18]

To develop this problem it is necessary to apply the concepts related to Gravitational Potential Energy.

Gravitational potential energy can be defined as

PE = -\frac{GMm}{R}

As M=m, then

PE = -\frac{Gm^2}{R}

Where,

m = Mass

G =Gravitational Universal Constant

R = Distance /Radius

PART A) As half its initial value is u'=2u, then

U = -\frac{2Gm^2}{R}

dU = -\frac{2Gm^2}{R}

dKE = -dU

Therefore replacing we have that,

\frac{1}{2}mv^2 =\frac{Gm^2}{2R}

Re-arrange to find v,

v= \sqrt{\frac{Gm}{R}}

v = \sqrt{\frac{6.67*10^{-11}*1*10^{28}}{1*10^{12}}}

v = 816.7m/s

Therefore the  velocity when the separation has decreased to one-half its initial value is 816m/s

PART B) With a final separation distance of 2r, we have that

2r = 2*10^3m

Therefore

dU = Gm^2(\frac{1}{R}-\frac{1}{2r})

v = \sqrt{Gm(\frac{1}{2r}-\frac{1}{R})}

v = \sqrt{6.67*10^{-11}*10^{28}(\frac{1}{2*10^3}-\frac{1}{10^{12}})}

v = 1.83*10^7m/s

Therefore the velocity when they are about to collide is 1.83*10^7m/s

7 0
3 years ago
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