Non-metals have a larger number of outer electrons called valence electrons. Therefore, it is easier for them to "steal" valance electrons from other elements with fewer valence electrons(usually metals)
For example, Chlorine(Cl) has 7 ve-. When forming an ion it will steal one electron from a metal. and gain a charge of -1. Because the ion is NEGATIVELY charged, it will be called an anion.
Nonmetals form anions.
Vocab:
cation: Paws-itively charged ions (get it? because its a CAT ion?)
anion: negatively charged ions
Answer:
42.8
Explanation:
A particle travelling through potential difference V has energy E =qV = 1/2mv²
v = √(2qV / m)
ve = √(2qV / me)
vh = √(2qV / mh)
ve / vh = √( (2qV / me) ÷(2qV / mh) = √ ( mh / me ) where mh = mass of hydrogen ion and me is mass of electron, V voltage is the same, ve is speed of electron and vh is the speed of hydrogen ion
ve / vh = √ ( mh / me ) = √ ( 1.67 × 10⁻²⁷ kg) / ( 9.11 × 10 ⁻³¹ kg) = 42.8
Answer:
Mixing colored lights & mixing colored paints. The primary colors of light are also known as the additive colors, because, when you add these three colors of light (red, green and blue) your brain perceives white light. The primary colors of paints, however, are known as subtractive colors.
Explanation:
<em>Your </em><em>well-wisher</em>
Answer:
On the particulate level: 1 molecule of H₂(g) reacts with 1 molecule of Cl₂(g) to form 2 molecules of HCl(g).
On the molar level: 1 mole of H₂(g) reacts with 1 mole of Cl₂(g) to form 2 moles of HCl(g).
Explanation:
Let's consider the following equation.
H₂(g) + Cl₂(g) → 2 HCl(g)
We can use the balanced equation to interpret the changes in two levels: the particulate level and the molar level.
On the particulate level, we consider discrete molecules.
On the particulate level: 1 molecule of H₂(g) reacts with 1 molecule of Cl₂(g) to form 2 molecules of HCl(g).
On the molar level, we think in terms of moles, considering 1 mole of particles = 6.02 × 10²³ particles.
On the molar level: 1 mole of H₂(g) reacts with 1 mole of Cl₂(g) to form 2 moles of HCl(g).
