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andreyandreev [35.5K]
4 years ago
7

Interpret the following equation for a chemical reaction using the coefficients given: H2(g) + Cl2(g) 2 HCl(g) On the particulat

e level: of H2(g) reacts with of Cl2(g) to form of HCl(g). On the molar level: of H2(g) reacts with of Cl2(g) to form of HCl(g).
Chemistry
1 answer:
jeyben [28]4 years ago
7 0

Answer:

On the particulate level: 1 molecule of H₂(g) reacts with 1 molecule of Cl₂(g) to form 2 molecules of HCl(g).

On the molar level: 1 mole of H₂(g) reacts with 1 mole of Cl₂(g) to form 2 moles of HCl(g).

Explanation:

Let's consider the following equation.

H₂(g) + Cl₂(g) → 2 HCl(g)

We can use the balanced equation to interpret the changes in two levels: the particulate level and the molar level.

On the particulate level, we consider discrete molecules.

On the particulate level: 1 molecule of H₂(g) reacts with 1 molecule of Cl₂(g) to form 2 molecules of HCl(g).

On the molar level, we think in terms of moles, considering 1 mole of particles = 6.02 × 10²³ particles.

On the molar level: 1 mole of H₂(g) reacts with 1 mole of Cl₂(g) to form 2 moles of HCl(g).

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Determine la cantidad aproximada de nitrato potásico (NaNO3) que habrá que mezclar con 150 g de agua para obtener una disolución
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Determine the approximate amount of potassium nitrate (NaNO3) that must be mixed with 150 g of water to obtain a saturated solution at 10ºC.

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Please help me, Thank you!
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2

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3 years ago
What is the molar solubility of aucl3 (ksp = 3. 2 x 10-23) in a 0. 013 m solution of magnesium chloride (a soluble salt)?
Inessa [10]

The molar solubility of AuCl₃ in a 0.013 M solution of magnesium chloride is 1.81×10⁻²⁸M.

<h3>What is Ksp?</h3>

The solubility product constant, Ksp, is the equilibrium constant for a solid substance dissolving in an aqueous solution. And for the AuCl₃, Ksp will be written as: Ksp = [Au³⁺][Cl⁻]³

Let the solubility of the AuCl₃ in 0.013M solution of magnesium chloride is x, of Au³⁺ is x and of Cl⁻ is 3x. But we know that MgCl₂ is a strong electrolyte and it completely dissociates into its ions and will produce 2 moles of chloride ions. For this solution let we consider the volume is 1 liter then the concentration of chloride ions in MgCl₂ is 2(0.013)=0.026M.

So, in MgCl₂ solution concentration of Cl⁻ becomes = 3x + 0.026.

Value of Ksp for AuCl₃ = 3.2 × 10⁻²³

On putting all values on the Ksp equation, we get

Ksp = (x)(3x + 0.026)³

Value of 3x is negligible as compared to the 0.026, so the equation becomes

3.2 × 10⁻²³ = (x)(0.026)³

x = 3.2×10⁻²³ / (0.026)³

x = 1.81×10⁻²⁸M

Hence the molar solubility of AuCl₃ in 0.010M MgCl₂ is 1.81×10⁻²⁸M.

To know more about molar solubility, visit the below link:

brainly.com/question/27308068

#SPJ4

4 0
3 years ago
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