The answer to your question is "Participant Observation".
Answer:
NH4Cl > Li2SO4 > CoCl3
Explanation:
Let us recall that the freezing point depression depends on the molality of the solution and the number of particles present.
Let us also recall that freezing point depression is a colligative property. It depends on the number of particles present in solution.
Usually, the more the number of particles present, the lower the freezing point. Hence, NH4Cl which has only two particles will have the highest freezing point while CoCl3 which has four particles will have the lowest freezing point.
Answer: C - B - A - D
Explanation:
-Obtain a flask that is thoroughly cleaned
-Add the desired amount of stock solution
-Add deionized water until the volume reaches the mark on the flask.
- Cap the flask and invert several times to thoroughly mix the solution.
Answer:
KCl ⇒ 1.205x10²⁴ molecules
O₂ ⇒ 1.807x10²⁴ molecules
KClO₃ ⇒ 1.205x10²⁴ molecules
Explanation:
In order to calculate the number of particles from the number of moles, we have to use Avogadro's number, which states <em>the number of particles in one mol</em>:
- In 1 mol there are 6.023x10²³ particles (ions, molecules or atoms).
So now we <u>multiply the number of moles of each substance by Avogadro's number</u>:
- KCl ⇒ 2 mol * 6.023x10²³ molecules/mol = 1.205x10²⁴ molecules
- O₂ ⇒ 3 mol * 6.023x10²³ molecules/mol = 1.807x10²⁴ molecules
- KClO₃ ⇒ 2 mol * 6.023x10²³ molecules/mol = 1.205x10²⁴ molecules
A.) Phosphate ion or Orthophosphate
d.) Hydroxide
D.) Ammonium
e.) Iron
C.) Nitrate
f.) Sulfur dioxide
