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wariber [46]
2 years ago
9

There are 20 teachers and 705 students in Corey's school.

Mathematics
2 answers:
Marina86 [1]2 years ago
8 0
The correct answer is B
goblinko [34]2 years ago
4 0

Answer:

<em><u>all </u></em><em><u>the </u></em><em><u>options </u></em><em><u>are </u></em><em><u>incorrect </u></em>

Given - 20 teachers

- 705 students

To find - ratio of teachers to students

20/705

20 : 705 .

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May someone please help me please? This is about exponents by the way. About 5 questions I need help with.
Sloan [31]

Answer:

2x2x2x2x2x2x2=8/3=1 2/3

8x8x8=512

1/6x1/6x1/6= 1/216

5/8x5/8=1 2/8

Step-by-step explanation:

i hope this helps

have a nice day/night

mark brainliest, please :)

6 0
3 years ago
What is equivalent to 6/8?
patriot [66]
3/4
75%
0.75
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4 0
3 years ago
HELP PLZ!!!!!!!!!!! WILL GIVE BRAIN!!!!!!!
irina1246 [14]

Answer: 1 go to 1 the 2 go to 5 the 3 go to 3 the 4 go to 2 the 5 go to 4

Step-by-step explanation: i hop this helps if not sorry :(

3 0
3 years ago
Please help with this geometry math problem!
valina [46]

Answer:

∠8 * 4 = ∠7 ----------------(1)

∠8 + ∠7 = 180 ------------(2)

Taking the value of ∠7 from (1) and using it in (2):

<u><em>∠7 = 4 * ∠8</em></u>

<u><em /></u>

∠8 + ∠7 = 180

∠8 + (4 * ∠8) = 180

∠8 + 4∠8 = 180

5∠8 = 180

∠8 = 36° ---------------(3)

Using the value of ∠8 from (3) in (2):

∠8 + ∠7 = 180

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∠7 = 144°       and       ∠8 = 36°

4 0
4 years ago
Judy’s brother Sam has a collection of 96 comic books what are the 10 where is Sam could divide his comic books into equal group
sweet-ann [11.9K]

We have been given that Judy’s brother Sam has a collection of 96 comic books. We have been asked to find the 10 ways Sam could divide his comic books into equal groups.

This can be done as follows:

96 can be written as 2\times 48=48\times 2=96. Thus, we can either have 2 groups of 48 comics or 48 groups of 2 comics. As we can see we have 2 ways to divide the comic books in equal groups.

Likewise, 96 can also be written as 3\times 32=32\times 3=96. Here, we can similarly see that we can either have 3 groups of 32 comics or 32 groups of 3 comics. As we can again see we have 2 more ways to divide the comic books in equal groups, taking the total number of ways to 4.

Continuing in this manner we will see that we can have 4 groups of 24 or 24 groups of 4, 6 groups of 16 or 16 groups of 6 and lastly 12 groups of 8 or 8 groups of 12 comic books, thus taking the count to a <u>total of 10 ways</u> in which Sam can divide his comic books into equal groups.

Our question has been answered.

5 0
3 years ago
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