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1 year ago

10

If -8. min 19 are in an AP, find the values of m and n

1 answer:

NeX [460]1 year ago

5 0

Answer:

m = 1 and n = 10.

Step-by-step explanation:

I am assuming you mean -8, m , n, 19.

If they are in AP the 4 terms will have a common difference.

19 - (-8) = 19 + 8 = 27.

So the increase over 3 terms (from -8 to 19) is 27 so we have:

27 / 3 = 9

Therefore the common difference is 9 and the A P is

-8, 1, 10, 19.

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Find the surface area of the cylinder to the nearest tenth. Use 3.14 for n

zaharov [31]

Remember: The formula for surface area for cylinders are S= 2πrh + 2πr²
The 2πr² represents the circular parts of the cylinder.

First, let's find the lateral side of the cylinder.
→ 2 (3.14)(6)(15) = 565.2
Next, find the circular parts.
→ 2 (3.14)(6²)
→ 2 (3.14)(36) = 226.08
Add the two answers together.
→565.2 + 226.08 = 791.28
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I hope this helps!

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2 years ago

Solve the following system of equations:

Talja [164]

Answer:

x=1,y=3

correct answer is (1,3)

Step-by-step explanation:

We can quickly eliminate y by subtracting one equation from the other

(-2x+y=1)-(-4x+y=-1)

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plug x=1 into equation 1

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2 years ago

Sarah had 20 apples, If adam stole 15 of them, how many does sarah have now?

Rina8888 [55]

Answer:

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Step-by-step explanation:

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3 years ago

Help me with this pls thank you

Crazy boy [7]

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3 years ago

Is my answer correct? 10 points + brainleist!

Liono4ka [1.6K]

Answer:

your answer is incorrect. The correct answer is $h=-13$ and $k=13$ .

Step-by-step explanation:

If a quadratic function is $f(x)=ax^2+bx+c$ and a>0, then minimum value of the function at point $\left(-\dfrac{b}{2a},f(-\dfrac{b}{2a})\right)$ .

The given function is

$f(x)=x^2+bx+182$

Here, a=1, b=b and c=182. So.

$-\dfrac{b}{2a}=-\dfrac{b}{2(1)}=-\dfrac{b}{2}$

Put $x=-\dfrac{b}{2}$ in the given function to find the minimum value of the function.

$f(-\dfrac{b}{2})=(-\dfrac{b}{2})^2+b(-\dfrac{b}{2})+182$

We know that minimum value is 13. So,

$13=\dfrac{b^2}{4}-\dfrac{b^2}{2}+182$

$13-182=-\dfrac{b^2}{4}$

$-169=-\dfrac{b^2}{4}$

$169\times 4=b^2$

Taking square root on both sides.

$13\times 2=b$

$b=26$

The value of b is 26.

So, the given function is

$f(x)=x^2+26x+182$

Now, add and subtract square of half of coefficient of x.

$f(x)=x^2+26x+182+(13)^2-(13)^2$

$f(x)=(x^2+2(13)x+(13)^2)+182-169$

$f(x)=(x+13)^2+13$

On comparing with $f(x)=(x-h)^2+k$ , we get

$h=-13$

$k=13$

Therefore, your answer is incorrect.

8 0

2 years ago