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iogann1982 [59]
2 years ago
8

Triangles J K L and M N R are shown.

Mathematics
1 answer:
Free_Kalibri [48]2 years ago
4 0

The correct answer is option B which is we need ∠L ≅  ∠R to prove congruency.

<h3>What is congruency?</h3>

The Side-Angle-Side Congruence Theorem (SAS) defines two triangles to be congruent to each other if the included angle and two sides of one is congruent to the included angle and corresponding two sides of the other triangle.

According to the SAS theorem which means Side Angle Side, The angle which is included between the two sides must be congruent.

Here we are given that

KL = NR

JL = MR

Now in the figure, we can clearly see that the angle included between JL & KL is L & the angle included between NR & MR is R.

So for the triangles to be congruent by SAS, angle L must be congruent to angle R.

∠L=∠R

Therefore the correct answer is option B which is we need ∠L ≅ ∠R to prove congruency.

Learn more about congruency at

brainly.com/question/14418374

#SPJ1

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How many outfits can you get from 5 suits, 7 shirts, 4 ties and 6 hats
Vaselesa [24]

Answer:

840 outfits

Step-by-step explanation:

4 0
3 years ago
Men consume on average 15 grams of protein a day. Assume a normal distribution with a standard deviation of 3 grams. A sample of
tatyana61 [14]

Using the normal distribution, there is a 0.4826 = 48.26% probability that the sample mean is between 15 and 16 grams per day.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

For this problem, the parameters are given as follows:

\mu = 15, \sigma = 3, n = 40, s = \frac{3}{\sqrt{40}} = 0.4743

The probability is the <u>p-value of Z when X = 16 subtracted by the p-value of Z when X = 15</u>, hence:

X = 16:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{16 - 15}{0.4743}

Z = 2.11

Z = 2.11 has a p-value of 0.9826.

X = 15:

Z = \frac{X - \mu}{s}

Z = \frac{15 - 15}{0.4743}

Z = 0

Z = 0 has a p-value of 0.5.

0.9826 - 0.5 = 0.4826 = 48.26% probability that the sample mean is between 15 and 16 grams per day.

More can be learned about the normal distribution at brainly.com/question/15181104

#SPJ1

4 0
1 year ago
GIVING BRAINLIEST!!!
lord [1]

Answer:

D.

Explanation:

PEMDAS method. First do the parentheses. Multiply first, then subtract 12 from that number. Once finished with the parentheses, multiply by 8.

7 0
3 years ago
1) Are the following lines parallel, perpendicular, or neither?
Maru [420]
In 1)

Line 1 has following coordinates.
(0,0) ; (1,-2) ; (2,-4)

Line 2 has following coordinates.
(0,0) ; (1,0.5) ; (2,1)

Line 3 has following coordinates.
(0,1) ; (1,1.5) ; (2,2)

If you'll draw the lines, you'll observe that Line 1 is perpendicular to Line 2 and Line 3 and Line 2 and Line 3 are parallel to each other.

So,
Option D will be correct.

5 0
3 years ago
A transformation T : (x, y) → (x + 3, y + 1). Find the preimage of the point (4, 3) under the given transformation. (7, 4) (1, 2
motikmotik

Answer:

(1, 2)

Step-by-step explanation:

Remember that the final shape and position of a figure after a transformation is called the image, and the original shape and position of the figure is the pre-image.

In our case, our figure is just a point. We know that after the transformation T : (x, y) → (x + 3, y + 1), our image has coordinates (4, 3).

The transformation rule T : (x, y) → (x + 3, y + 1) means that we add 3 to the x-coordinate and add 1 to the y-coordinate of our pre-image. Now to find the pre-image of our point, we just need to reverse those operations; in other words, we will subtract 3 from the x-coordinate and subtract 1 from the y-coordinate.

So, our rule to find the pre-image of the point (4, 3) is:

T : (x, y) → (x - 3, y - 1)

We know that the x-coordinate of our image is 4 and its y-coordinate is 3.

Replacing values:

                (4 - 3, 3 - 1)

                (1, 2)

We can conclude that our pre-image is the point (1, 2).

6 0
2 years ago
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