Since (f/g)(x) = f(x)/g(x) for x to be in the domain of (f/g)(x) it must be in the domain of f and in the domain of g. You also need to insure that g(x) is not zero since f(x) is divided by g(x). Thus there are 3 conditions. x must be in the domain of f: f(x) = 3x -5 and all real numbers x are in the domain of x.
Given f(x) = 2x + 3 and g(x) = –x2 + 5, find ( f o f )(x).
( f o f )(x) = f ( f (x))
= f (2x + 3)
= 2( ) + 3 ... setting up to insert the input
= 2(2x + 3) + 3
= 4x + 6 + 3
= 4x + 9
Given f(x) = 2x + 3 and g(x) = –x2 + 5, find (g o g)(x).
(g o g)(x) = g(g(x))
= –( )2 + 5 ... setting up to insert the input
= –(–x2 + 5)2 + 5
= –(x4 – 10x2 + 25) + 5
= –x4 + 10x2 – 25 + 5
= –x4 + 10x2 – 20
Answer:
Step-by-step explanation:
You want to use the distributive property for this one:
-7k + 21
Your answer should be the very bottom left one.
Hopefully thta helped! :)
Let's solve your equation step-by-step.
3−6(x−7)=42−6x
Step 1: Simplify both sides of the equation.
3−6(x−7)=42−6x
3+(−6)(x)+(−6)(−7)=42+−6x(Distribute)
3+−6x+42=42+−6x
(−6x)+(3+42)=−6x+42(Combine Like Terms)
−6x+45=−6x+42
−6x+45=−6x+42
Step 2: Add 6x to both sides.
−6x+45+6x=−6x+42+6x
45=42
Step 3: Subtract 45 from both sides.
45−45=42−45
0=−3
Therefore, this is No Solutions.
